C W?0 D W?Q??U
2£®Ñ¹Æø»úѹËõÆøÌåËùºÄÀíÂÛÖṦΪ£ß£ß£ß¡£
A ?pdv
122B ?d(pv)
12C ?pdv?p1v1?p2v2
13£®?w??cvdTÊÊÓÃÌõ¼þΪ£ß£ß£ß¡£
A ÀíÏëÆøÌå¿ÉÄæ¹ý³Ì C Èκι¤Öʶ¨Èݹý³Ì
B ÀíÏëÆøÌå¾øÈȹý³Ì£» D Èκι¤ÖʾøÈȹý³Ì
4£®q?cv?T??RdvÊÊÓÃÓڣߣߣߡ£
A ÀíÏëÆøÌå¿ÉÄæ¹ý³Ì C ÀíÏëÆøÌåÒ»Çйý³Ì
B Ò»ÇÐÆøÌå¿ÉÄæ¹ý³Ì D ÀíÏëÆøÌå×¼¾²Ì¬¹ý³Ì
5£®dq?dh??wtÖ»ÊÊÓÃÓڣߣߣߡ£
A ÀíÏëÆøÌå¿ÉÄæ¹ý³Ì C ÀíÏëÆøÌåÈκιý³Ì
B Èκι¤ÖÊÈκιý³Ì D Èκι¤ÖÊ¿ÉÄæ¹ý³Ì
6£®ÖüÓÐ¿ÕÆøµÄ¾øÈȸÕÐÔÃܱÕÈÝÆ÷ÖУ¬°²×°Óеç¼ÓÈÈË¿£¬Í¨µçºó£¬ÈçÈ¡¿ÕÆøÎªÏµÍ³£¬Ôò¹ý³ÌÖеÄÄÜÁ¿¹ØÏµÓÐ______
A Q>0 , ¦¤U>0 , W>0 C Q>0 , ¦¤U>0 , W=0
Èý¡¢Ìî¿Õ
1£®ÈÈÁ¿ÓëÅòÕ͹¦¶¼ÊÇ Á¿£¬ÈÈÄÜͨ¹ý ²î¶ø´«µÝ £¬ÅòÕ͹¦Í¨¹ý ´«µÝ ¡£
2£®±Õ¿Úϵͳq??hÊÊÓÃÓÚ ¹ý³Ì£¬¿ª¿Úϵͳq??hÊÊÓÃÓÚ ¡£
3£®ÄÜÁ¿·½³Ìʽq??h+wsÊÊÓõÄÌõ¼þÊÇ ¡£
4£®¹«Ê½?q??wÊÊÓÃÓÚÀíÏëÆøÌåµÄ ¹ý³Ì¡£
B Q=0 , ¦¤U>0 , W<0 D Q=0 , ¦¤U=0 , W=0
5£®¹«Ê½?q?dhÊÊÓÃÓÚÈÎºÎÆøÌåµÄ ¹ý³Ì¡£ 6£®¹«Ê½?ws??dhÊÊÓÃÓÚ ¹ý³Ì¡£
ËÄ¡¢Ãû´Ê½âÊÍ ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ ìÊ
ϵͳµÄ´¢´æÄÜ ¼¼Êõ¹¦ ÎÈ̬ÎÈÁ÷
Îå¡¢¼ÆËãÌâ
1£®lkg¿ÕÆø´Ó³õ̬p1=5bar£¬T1=340K¡£ÔÚ±Õ¿ÚϵͳÖнøÐпÉÄæ¾øÈÈÅòÕÍ£¬ÆäÈÝ»ý±äΪÔÀ´µÄ2±¶(v2?2v1)ÇóÖÕ̬ѹÁ¦¡¢Î¶ȡ¢ÄÚÄÜ¡¢ìʵı仯¼°ÅòÕ͹¦¡£
2£®Ñ¹Æø»ú²úÉúѹÁ¦Îª6bar£¬Á÷Á¿Îª20kg/sµÄѹËõ¿ÕÆø£¬ÒÑÖªÑ¹Æø»ú½ø¿Ú״̬p1=1bar£¬t1=20¡æ£¬ÈçΪ²»¿ÉÄæ¾øÈÈѹËõ£¬Êµ¼ÊÏûºÄ¹¦ÊÇÀíÂÛÖṦµÄ1.15±¶£¬ÇóÑ¹Æø»ú³ö¿ÚζÈt2¼°Êµ¼ÊÏûºÄ¹¦ÂÊP¡£
3£®ÆøÌå´Óp1=1bar£¬v1=0.3m3ѹËõµ½p2=4bar£¬Ñ¹Ëõ¹ý³ÌÖÐά³ÖÏÂÁйØÏµp=av+bÆäÖÐa=-15bar/m3£¬ÊÔ¼ÆËã¹ý³ÌÖÐËùÐèµÄ¹¦,²¢½«¹ý³Ì±íʾÔÚP-vͼÉÏ¡£