H2O = H+ + OH- Kw=1.00x 10-14 ÏÂÁз´Ó¦µÄƽºâ³£ÊýÊÇ________
NH3 + HCN = NH4+ + CN-
A. 8.82 x 10-29 B. 2.75 x 10-19 C. 8.82 x 10-1
43. ÏÂÁл¯ºÏÎïÖÐ,ÆäË®ÈÜÒºµÄPHÖµ×î¸ßµÄÊÇ________
A. NaCl B. Na2CO3 C. NH4Cl D. NaHCO3
44¡¢ ÔÚH2SµÄ±¥ºÍË®ÈÜÒºÖУ¬ÏÂÁÐŨ¶È¹ØÏµÕýÈ·µÄÊÇ¡ª¡ª¡ª¡ª¡ª
A. [S2-]¡Ö2[H+] B. [HS-]¡Ö[H+] C. [H2S]¡Ö[H+]+[HS-] D. [H2S]¡Ö[S2-]
45. ÏòHACÈÜÒºÖмÓһЩNaAC,»áʹ¡ª¡ª¡ª¡ª¡ª¡ª
A. HACµÄKa¼õÉÙ B. HAC µÄµçÀë¶È¼õÉÙ C. HACµÄH+Àë×ÓŨ¶ÈÔö¼Ó D. ÈÜÒºµÄPHÖµ¼õÉÙ
46. 0.10mol.l-1HACÈÜÒºÔÚ1Éý0.10mol.l-1NaACË®ÈÜÒºÖУ¬HACµÄµç
Àë¶ÈΪ¡ª¡ª¡ª¡ª¡ª¡ª¡ª
A. 10Ka% B. 1000Ka% C. 100Ka% D. 100¡ÌKa/0.1%
47. ÈõËáÐÔË®ÈÜÒºÖеÄÇâÀë×ÓŨ¶È¿É±íʾΪ_______
A. 14_POH B. KW/POH C. 10-POH D. 10-(14-POH)
48£® 0.20mol.l-1¼×ËáÈÜÒºÖÐ3.2%µÄ¼×ËáÒѵçÀ룬ËüµÄµçÀë³£ÊýÊÇ¡ª¡ª¡ª
A.2.1 x 10-4 B. 1.25 x 10-6 C. 4.8 x 10-5 D.2.1 x 10-8
49. Èç¹ûÒÒËáµÄÀë½â³£ÊýÊÇ1.75 x 10-5 mol.l-1,ÔòÒÔʲô±ÈÀý»ìºÏÒÒËáºÍÒÒËáÄÆµÃµ½PH=6.2µÄ»º³åÈÜÒº______
A. 6.3/17.5 B. 6.3/1.75 C. 6.3/35 D. 63/1.75
50¡¢ÔÚ0.30 mol.l-1µÄHClÈÜÒºÖÐͨH2SÖÁ±¥ºÍ£¬S2Ũ¶ÈΪÏÂÁÐÄÄÒ»Ï
£
£¨±¥ºÍH2SÈÜÒºÖУ¬H2SµÄŨ¶ÈΪ0.10mol¡¤L1£©
£
A¡¢0.10 mol.l-1 B¡¢0.30 mol.l-1 C¡¢Ka10¡¤Ka20 D¡¢1.1¡Á10
£19
mol.l-1
41
¶þ¡¢ Ìî¿ÕÌâ
1¡¢NH4+¡¢Cl-¡¢AC-¡¢H2OµÈÎïÖÊÖУ¬¼ÈÊÇÖÊ×ÓËáµÄÓÖÊÇÖÊ×Ó¼îµÄÎïÖÊÊÇ________£¬Æä¹²éîËáÊÇ_____________________¡¢¹²éî¼îÊÇ________________¡£
2¡¢ÓÉNaH2PO4ºÍNa2HPO4×é³É»º³åÈÜÒºÖеĻº³å¶ÔÎïÖÊÊÇ_ ________________________________¡£¸Ã»º³åÈÜÒºµÄ
»º³å×÷ÓõÄÓÐЧ·¶Î§PHÖµÊÇ_________________________¡£
3¡¢°´Ëá¼îÖÊ×ÓÀíÂÛ£¬[Al(H2O)5(OH)]2+µÄ¹²éî¼îÊÇ_______________£¬Æä¹²éîËáÊÇ____________________¡£ 4¡¢0.10mol.l-1 NaHCO3ÈÜÒºµÄPH = ________________£¬
0.10mol.l-1 Na2CO3ÈÜÒºµÄPH = _____________________
£¨H2CO3µÄPKa1 = 6.4, PKa2 = 10.2£©.
5¡¢ÅäÖÆ»º³åÈÜҺʱ£¬Ñ¡Ôñ»º³å¶ÔµÄÔÔòÊÇ__________________________¡£
6¡¢ÒÑÖª0.10mol.l-1 HACÆä[H+]=1.3 x 10-3 mol.l-1 ,ÔòHACµÄµçÀë¶ÈΪ_________£¬µçÀëÆ½ºâ³£ÊýΪ____________________¡£ 7¡¢ÔÚH2S±¥ºÍÈÜÒºÖÐ[S2-]½üËÆµÈÓÚ_________________¡£
8¡¢ÒÑÖªH3PO4µÄPKa1 =2.1, PKa2 = 7.2 £¬PKa3= 12.6£¬ÓÃÁ×ËáÑÎÅäÖÆ
»º³åÈÜҺʱ,ÈôÑ¡ÓÃNa2HPO4 ×÷ΪËᣬ¿ÉÅä³ÉPHÔÚ_______________·¶Î§µÄ»º³åÈÜÒº£»ÈôÑ¡ÓÃNa2HPO4 ×÷Ϊ¼î£¬¿ÉÅäÖÆ³ÉPHÔÚ____________________·¶Î§µÄ»º³åÈÜÒº¡£ 9¡¢ÔÚ50ml 0.12mol.l-1 µÄH3PO4ÈÜÒºÖмÓÈë60ml 0.20mol.l-1NaOH
ÈÜÒº£¬Ôò»ìºÏÈÜÒºµÄPH = ______________________¡£ÔÚ60ml 0.10mol.l-1µÄNa3PO4ÈÜÒºÖмÓÈë50ml0.20mol.l-1 HClÈÜÒº£¬Ôò»ìºÏÈÜÒºµÄPH = __________________¡£
10£®Àë½â¶È¦Á¡¢Àë½â³£ÊýKÓëŨ¶ÈCµÄ¹ØÏµÊÇ£º________________ËæÅ¨¶È
C¶ø±ä£¬¶ø________²»ËæÅ¨¶ÈC¶ø±ä¡£Ï¡ÊͶ¨ÂɵÄÊýѧ±íʾʽΪ__________¡£ 11£®ÒªÊ¹0.1Éý4.0 mol.l-1µÄNH3Ë®µÄÀë½â¶ÈÔö´ó1±¶£¬Ðè¼ÓÈëË®____
______Éý¡£
12£®0.10 mol.l-1 µÄH2SÈÜÒºÖУ¬H+Ũ¶ÈÊÇ9.5 x 10-5 mol.l-1 ,PH =_______£¬HS-Àë×ÓŨ¶È_____________mol.l-1£¬S2-Àë×ÓŨ¶ÈΪ________mol.l-1¡£
13£®·Ö±ðÖкÍͬÌå»ýµÄPHÏàͬµÄNaOHºÍNH3Ë®ÈÜÒº£¬ËùÐèHClÈÜÒºµÄÁ¿Îª_____________£»Öк͵ÈÌå»ýµÈŨ¶È
42
µÄHClºÍHACÈÜÒº£¬ËùÐèµÄNaOHµÄÁ¿Îª__________________¡££¨ÌîÏàµÈ»ò²»ÏàµÈ£©
14£®PHΪ3.0µÄÏÂÁÐÈÜÒº£¬ÓõÈÌå»ýµÄË®³åÊͺó£¬HACÈÜÒºPHΪ_________£»HClÈÜÒºPHΪ_____________£»HAC
¡ªNaACÈÜÒºPHΪ____________¡£
15£®ÓÚ0.1Éý0.10 mol.l-1 µÄHACÈÜÒºÖмÓÈë0.01mol¹ÌÌåNaAc£¨¼ÙÉèÌå»ý²»±ä£©ÔòÈÜÒºÖеÄH+Àë×ÓŨ¶È½«»á
__________£»PH
½«»á____________£¬AC-Àë×ÓŨ¶È½«»á_________£¨ÌîÔö´ó¡¢¼õС»ò²»±ä£©¡£¸Ã»ìºÏÈÜÒº³ÆÎª__________
ÈÜÒº£¬ÆäH+Àë×ÓŨ¶ÈΪ______ mol.l-1£¬Ïò¸ÃÈÜÒºÖмÓÈëÉÙÁ¿Ëá¡¢¼î»òË®ºó£¬ÈÜÒºPHΪ____¡£
16£®CO32-µÄ·Ö¼¶Ë®½â³£ÊýKn1ÓÚKn2ºÍH2CO3ÈÜÒºµÄ·Ö¼¶Àë½â³£ÊýKa1¡¢Ka2Ö®¼äµÄ¹ØÏµÊÇKn1 = ______________£¬
Kn2 =_____¡£
17£®¸ù¾ÝÖÊ×ÓÀíÂÛ£¬NH4+¡¢PO43+¡¢HCO3-¡¢S2-¡¢H3PO4ºÍAC-Àë×ÓÖÐÊÇÖÊ×ÓËá µÄÓÐ________£¬Æä¹²éî¼î·ÖÊÇ_______£»
ÊÇÖÊ×Ó¼îµÄÓÐ____________£¬Æä¹²éîËá·Ö±ðÊÇ______________________£»ÆäÖмÈÊÇËáÓÖÊǼîµÄÓÐ
__________________________¡£
Èý¡¢¼ÆËãÌâ
1¡¢¼ÆËã0.20 mol.l-1 Na2CO3Ë®ÈÜÒºµÄPHÖµ¡£ÈôÏò¸ÃÈÜÒºÖмÓÈëµÈÌå»ýµÄ0.20mol.l-1HCl£¬¼ÆËã»ìºÏÒºµÄPHÖµ
(H2CO3µÄKa1=4.3 x 10-7, Ka2=5.6x 10-11).
2¡¢ÅäÖÆPH = 8.25µÄ»º³åÈÜÒº£¬ÎÊÔÚ200ml 0.20 mol.l-1 NH3H2O ÖмÓÈë0.50 mol.l-1 HCl¶àÉÙºÁÉý?
(ÒÑÖªNH3.H2OµÄPKb = 4.75).
43
3¡¢½«10ml, 0.30 mol.l-1 µÄHCOONaÓë20ml, 0.15 mol.l-1µÄHF»ìºÏ.¼ÆËã·´Ó¦µÄƽºâ³£ÊýºÍÈÜÒºÖеÄ[HCOO-]¡¢
[F-]ºÍ[H+]¸÷Ϊ¶àÉÙ?
(KHCOOH = 1.7 x 10-4, KHF = 6.8 x 10-4).
4. ÒÑÖª298KʱijһԪÈõËáµÄ0.10 mol.l-1Ë®ÈÜÒºµÄPHֵΪ3.0, Çó: (1) Ka (2) ¦Á (3)Ï¡ÊÍÒ»±¶ºóµÄKa¡¢¦Á¡¢PHÖµ
£¨4£©Óë0.10 mol.l-1 NaOHÈÜÒºµÈÌå»ý»ìºÏºóËùµÃ»ìºÏÈÜÒºµÄPHÖµ Ìå»ý»ìºÏºóËùµÃ»ìºÏÈÜÒºµÄPHÖµ¡£
44
5£©Óë0.20 mol.l-1 NaOHÈÜÒºµÈ £¨