.archivetempÆÕͨ»¯Ñ§Ï°Ì⼯(1) ÏÂÔØ±¾ÎÄ

H2O = H+ + OH- Kw=1.00x 10-14 ÏÂÁз´Ó¦µÄƽºâ³£ÊýÊÇ________

NH3 + HCN = NH4+ + CN-

A. 8.82 x 10-29 B. 2.75 x 10-19 C. 8.82 x 10-1

43. ÏÂÁл¯ºÏÎïÖÐ,ÆäË®ÈÜÒºµÄPHÖµ×î¸ßµÄÊÇ________

A. NaCl B. Na2CO3 C. NH4Cl D. NaHCO3

44¡¢ ÔÚH2SµÄ±¥ºÍË®ÈÜÒºÖУ¬ÏÂÁÐŨ¶È¹ØÏµÕýÈ·µÄÊÇ¡ª¡ª¡ª¡ª¡ª

A. [S2-]¡Ö2[H+] B. [HS-]¡Ö[H+] C. [H2S]¡Ö[H+]+[HS-] D. [H2S]¡Ö[S2-]

45. ÏòHACÈÜÒºÖмÓһЩNaAC,»áʹ¡ª¡ª¡ª¡ª¡ª¡ª

A. HACµÄKa¼õÉÙ B. HAC µÄµçÀë¶È¼õÉÙ C. HACµÄH+Àë×ÓŨ¶ÈÔö¼Ó D. ÈÜÒºµÄPHÖµ¼õÉÙ

46. 0.10mol.l-1HACÈÜÒºÔÚ1Éý0.10mol.l-1NaACË®ÈÜÒºÖУ¬HACµÄµç

Àë¶ÈΪ¡ª¡ª¡ª¡ª¡ª¡ª¡ª

A. 10Ka% B. 1000Ka% C. 100Ka% D. 100¡ÌKa/0.1%

47. ÈõËáÐÔË®ÈÜÒºÖеÄÇâÀë×ÓŨ¶È¿É±íʾΪ_______

A. 14_POH B. KW/POH C. 10-POH D. 10-(14-POH)

48£® 0.20mol.l-1¼×ËáÈÜÒºÖÐ3.2%µÄ¼×ËáÒѵçÀ룬ËüµÄµçÀë³£ÊýÊÇ¡ª¡ª¡ª

A.2.1 x 10-4 B. 1.25 x 10-6 C. 4.8 x 10-5 D.2.1 x 10-8

49. Èç¹ûÒÒËáµÄÀë½â³£ÊýÊÇ1.75 x 10-5 mol.l-1,ÔòÒÔʲô±ÈÀý»ìºÏÒÒËáºÍÒÒËáÄÆµÃµ½PH=6.2µÄ»º³åÈÜÒº______

A. 6.3/17.5 B. 6.3/1.75 C. 6.3/35 D. 63/1.75

50¡¢ÔÚ0.30 mol.l-1µÄHClÈÜÒºÖÐͨH2SÖÁ±¥ºÍ£¬S2Ũ¶ÈΪÏÂÁÐÄÄÒ»Ï

£­

£¨±¥ºÍH2SÈÜÒºÖУ¬H2SµÄŨ¶ÈΪ0.10mol¡¤L1£©

£­

A¡¢0.10 mol.l-1 B¡¢0.30 mol.l-1 C¡¢Ka10¡¤Ka20 D¡¢1.1¡Á10

£­19

mol.l-1

41

¶þ¡¢ Ìî¿ÕÌâ

1¡¢NH4+¡¢Cl-¡¢AC-¡¢H2OµÈÎïÖÊÖУ¬¼ÈÊÇÖÊ×ÓËáµÄÓÖÊÇÖÊ×Ó¼îµÄÎïÖÊÊÇ________£¬Æä¹²éîËáÊÇ_____________________¡¢¹²éî¼îÊÇ________________¡£

2¡¢ÓÉNaH2PO4ºÍNa2HPO4×é³É»º³åÈÜÒºÖеĻº³å¶ÔÎïÖÊÊÇ_ ________________________________¡£¸Ã»º³åÈÜÒºµÄ

»º³å×÷ÓõÄÓÐЧ·¶Î§PHÖµÊÇ_________________________¡£

3¡¢°´Ëá¼îÖÊ×ÓÀíÂÛ£¬[Al(H2O)5(OH)]2+µÄ¹²éî¼îÊÇ_______________£¬Æä¹²éîËáÊÇ____________________¡£ 4¡¢0.10mol.l-1 NaHCO3ÈÜÒºµÄPH = ________________£¬

0.10mol.l-1 Na2CO3ÈÜÒºµÄPH = _____________________

£¨H2CO3µÄPKa1 = 6.4, PKa2 = 10.2£©.

5¡¢ÅäÖÆ»º³åÈÜҺʱ£¬Ñ¡Ôñ»º³å¶ÔµÄÔ­ÔòÊÇ__________________________¡£

6¡¢ÒÑÖª0.10mol.l-1 HACÆä[H+]=1.3 x 10-3 mol.l-1 ,ÔòHACµÄµçÀë¶ÈΪ_________£¬µçÀëÆ½ºâ³£ÊýΪ____________________¡£ 7¡¢ÔÚH2S±¥ºÍÈÜÒºÖÐ[S2-]½üËÆµÈÓÚ_________________¡£

8¡¢ÒÑÖªH3PO4µÄPKa1 =2.1, PKa2 = 7.2 £¬PKa3= 12.6£¬ÓÃÁ×ËáÑÎÅäÖÆ

»º³åÈÜҺʱ,ÈôÑ¡ÓÃNa2HPO4 ×÷ΪËᣬ¿ÉÅä³ÉPHÔÚ_______________·¶Î§µÄ»º³åÈÜÒº£»ÈôÑ¡ÓÃNa2HPO4 ×÷Ϊ¼î£¬¿ÉÅäÖÆ³ÉPHÔÚ____________________·¶Î§µÄ»º³åÈÜÒº¡£ 9¡¢ÔÚ50ml 0.12mol.l-1 µÄH3PO4ÈÜÒºÖмÓÈë60ml 0.20mol.l-1NaOH

ÈÜÒº£¬Ôò»ìºÏÈÜÒºµÄPH = ______________________¡£ÔÚ60ml 0.10mol.l-1µÄNa3PO4ÈÜÒºÖмÓÈë50ml0.20mol.l-1 HClÈÜÒº£¬Ôò»ìºÏÈÜÒºµÄPH = __________________¡£

10£®Àë½â¶È¦Á¡¢Àë½â³£ÊýKÓëŨ¶ÈCµÄ¹ØÏµÊÇ£º________________ËæÅ¨¶È

C¶ø±ä£¬¶ø________²»ËæÅ¨¶ÈC¶ø±ä¡£Ï¡ÊͶ¨ÂɵÄÊýѧ±íʾʽΪ__________¡£ 11£®ÒªÊ¹0.1Éý4.0 mol.l-1µÄNH3Ë®µÄÀë½â¶ÈÔö´ó1±¶£¬Ðè¼ÓÈëË®____

______Éý¡£

12£®0.10 mol.l-1 µÄH2SÈÜÒºÖУ¬H+Ũ¶ÈÊÇ9.5 x 10-5 mol.l-1 ,PH =_______£¬HS-Àë×ÓŨ¶È_____________mol.l-1£¬S2-Àë×ÓŨ¶ÈΪ________mol.l-1¡£

13£®·Ö±ðÖкÍͬÌå»ýµÄPHÏàͬµÄNaOHºÍNH3Ë®ÈÜÒº£¬ËùÐèHClÈÜÒºµÄÁ¿Îª_____________£»Öк͵ÈÌå»ýµÈŨ¶È

42

µÄHClºÍHACÈÜÒº£¬ËùÐèµÄNaOHµÄÁ¿Îª__________________¡££¨ÌîÏàµÈ»ò²»ÏàµÈ£©

14£®PHΪ3.0µÄÏÂÁÐÈÜÒº£¬ÓõÈÌå»ýµÄË®³åÊͺó£¬HACÈÜÒºPHΪ_________£»HClÈÜÒºPHΪ_____________£»HAC

¡ªNaACÈÜÒºPHΪ____________¡£

15£®ÓÚ0.1Éý0.10 mol.l-1 µÄHACÈÜÒºÖмÓÈë0.01mol¹ÌÌåNaAc£¨¼ÙÉèÌå»ý²»±ä£©ÔòÈÜÒºÖеÄH+Àë×ÓŨ¶È½«»á

__________£»PH

½«»á____________£¬AC-Àë×ÓŨ¶È½«»á_________£¨ÌîÔö´ó¡¢¼õС»ò²»±ä£©¡£¸Ã»ìºÏÈÜÒº³ÆÎª__________

ÈÜÒº£¬ÆäH+Àë×ÓŨ¶ÈΪ______ mol.l-1£¬Ïò¸ÃÈÜÒºÖмÓÈëÉÙÁ¿Ëá¡¢¼î»òË®ºó£¬ÈÜÒºPHΪ____¡£

16£®CO32-µÄ·Ö¼¶Ë®½â³£ÊýKn1ÓÚKn2ºÍH2CO3ÈÜÒºµÄ·Ö¼¶Àë½â³£ÊýKa1¡¢Ka2Ö®¼äµÄ¹ØÏµÊÇKn1 = ______________£¬

Kn2 =_____¡£

17£®¸ù¾ÝÖÊ×ÓÀíÂÛ£¬NH4+¡¢PO43+¡¢HCO3-¡¢S2-¡¢H3PO4ºÍAC-Àë×ÓÖÐÊÇÖÊ×ÓËá µÄÓÐ________£¬Æä¹²éî¼î·ÖÊÇ_______£»

ÊÇÖÊ×Ó¼îµÄÓÐ____________£¬Æä¹²éîËá·Ö±ðÊÇ______________________£»ÆäÖмÈÊÇËáÓÖÊǼîµÄÓÐ

__________________________¡£

Èý¡¢¼ÆËãÌâ

1¡¢¼ÆËã0.20 mol.l-1 Na2CO3Ë®ÈÜÒºµÄPHÖµ¡£ÈôÏò¸ÃÈÜÒºÖмÓÈëµÈÌå»ýµÄ0.20mol.l-1HCl£¬¼ÆËã»ìºÏÒºµÄPHÖµ

(H2CO3µÄKa1=4.3 x 10-7, Ka2=5.6x 10-11).

2¡¢ÅäÖÆPH = 8.25µÄ»º³åÈÜÒº£¬ÎÊÔÚ200ml 0.20 mol.l-1 NH3H2O ÖмÓÈë0.50 mol.l-1 HCl¶àÉÙºÁÉý?

(ÒÑÖªNH3.H2OµÄPKb = 4.75).

43

3¡¢½«10ml, 0.30 mol.l-1 µÄHCOONaÓë20ml, 0.15 mol.l-1µÄHF»ìºÏ.¼ÆËã·´Ó¦µÄƽºâ³£ÊýºÍÈÜÒºÖеÄ[HCOO-]¡¢

[F-]ºÍ[H+]¸÷Ϊ¶àÉÙ?

(KHCOOH = 1.7 x 10-4, KHF = 6.8 x 10-4).

4. ÒÑÖª298KʱijһԪÈõËáµÄ0.10 mol.l-1Ë®ÈÜÒºµÄPHֵΪ3.0, Çó: (1) Ka (2) ¦Á (3)Ï¡ÊÍÒ»±¶ºóµÄKa¡¢¦Á¡¢PHÖµ

£¨4£©Óë0.10 mol.l-1 NaOHÈÜÒºµÈÌå»ý»ìºÏºóËùµÃ»ìºÏÈÜÒºµÄPHÖµ Ìå»ý»ìºÏºóËùµÃ»ìºÏÈÜÒºµÄPHÖµ¡£

44

5£©Óë0.20 mol.l-1 NaOHÈÜÒºµÈ £¨