»¯Ñ§·ÖÎö£¨Î人´óѧ±à - µÚÎå°æ£©¿ÎºóϰÌâ´ð°¸ ÏÂÔØ±¾ÎÄ

¡à x?48.13%

25.³ÆÈ¡¸ÖÑù1.000g£¬Èܽâºó£¬½«ÆäÖеÄÁ׳ÁµíΪÁ×îâËáï§¡£ÓÃ20.00ml

-1

0.1000mol¡¤LNaOH

Èܽâ³Áµí£¬¹ýÁ¿µÄNaOHÓÃHNO3·µµÎ¶¨ÖÁ·Ó

-1

̪¸ÕºÃÍÊÉ«£¬ºÄÈ¥0.2000 mol¡¤L

HNO37.50mL¡£¼ÆËã¸ÖÖÐPºÍP2O5µÄÖÊÁ¿·ÖÊý¡£ ½â£ºP¡«(NH)HPO¡«12MoO¡«24NaOH¡« ¹ýÁ¿NaOH?0.2?7.5?10?1.5?10(mol) ÓÃÓڵζ¨Á×îâËáï§µÄ

NaOH?0.1?20?10?1.5?10?5.0?10(mol)

5.0?10?2.1?10(mol)º¬£ÐÎïÖʵÄÁ¿Îª£º24

42471P2O52?3?3?3?3?4?4?5

26.Ãæ·ÛÖдֵ°°×Öʺ¬Á¿Ó뵪º¬Á¿µÄ±ÈÀýϵÊýΪ5.7£¬2.449gÃæ·Û¾­¹ýÏû»¯ºó£¬ÓÃNaOH´¦Àí£¬½«Õô·¢³öµÄNH3ÓÃ100.0ml0.01086 mol¡¤L-1HClÈÜÒºÎüÊÕ£¬È»ºóÓÃ0.01228 -1

mol¡¤LNaOHÈÜÒºµÎ¶¨£¬ºÄÈ¥15.30ml£¬¼ÆËãÃæ·ÛÖдֵ°°×Öʺ¬Á¿¡£

½â£º

27.ÔÚ´¿Ë®ÖУ¬¼×»ù³ÈµÄÀíÂÛ±äÉ«µãPH=3.4£¬½ñÏòÈÜÒºÖмÓÈëNaClÈÜÒº£¬Ê¹ÆäŨ¶È´ïµ½-1

0.10 mol¡¤L¡£Îʼ׻ù³ÈµÄÀíÂÛ±äÉ«µãPHÓÖΪ¶àÉÙ£¿

2.1?10?5?31P%??100?0.06512.1?10?5?142P2O5%??100?0.151?2

(100?0.01086?0.01228?15.30)?14.01?5.7%?2.93%2.449?10

28. ±ê¶¨¼×´¼ÄÆÈÜҺʱ£¬³ÆÈ¡±½¼×Ëá0.4680g£¬ÏûºÄ¼×´¼ÄÆÈÜÒº25.50mL,Çó¼×´¼ÄƵÄŨ¶È¡£

½â£ºCH30Na¡«C6H5COOH£¬ÁîÆäŨ¶ÈΪc,

29.³ÆÈ¡²»´¿Ñõ»¯¹¯£¨¢ò£©ÊÔÑù0.6334g£¬ÈܽâÓÚ¹ýÁ¿KIÈÜÒººó£¬ÓÃHClµÎ¶¨£¬ºÄÈ¥0.1178 -1

mol¡¤LHCl 42.59ml£¬¼ÆËãÊÔÑùÖÐHgOµÄÖÊÁ¿·ÖÊý¡£

½â£º HgO + 2KI + H2O = HgI +2KOH

30.ȡij¼×È©ÈÜÒº10.00mlÓÚ×¶ÐÎÆ¿ÖУ¬ÏòÆäÖмÓÈë¹ýÁ¿µÄÑÎËáôǰ·£¬ÈÃËüÃdzä·Ö·´Ó¦£¬È»ºóÒÔäå·ÓÀ¶ÎªÖ¸Ê¾¼Á£¬ÓÃ0.1100 -1

mol¡¤LNaOHÈÜÒºµÎ¶¨·´Ó¦²úÉúµÄÓÎÀëËᣬºÄÈ¥28.45ml£¬¼ÆËã¼×È©ÈÜÒºµÄŨ¶È¡£ ½â£ºHCHO¡«NaOH

10.00¡ÁC = 28.45¡Á0.1100 -1 ¡àC =0.3129 mol¡¤L

1?0.1178?42.59?MHgO2%?85.78%0.6334?10c?0.4680?0.1500(mol/L)25.50?10?3?122µÚ6Õ ÂçºÏµÎ¶¨·¨

2. ÔÚPH=9.26µÄ°±ÐÔ»º³åÈÜÒºÖУ¬³ý°±ÂçºÏ-1ÎïÍâµÄ»º³å¼Á×ÜŨ¶ÈΪ0.20 mol¡¤L£¬ÓÎÀë2--12+C2O4Ũ¶ÈΪ0.10 mol¡¤L¡£¼ÆËãCuµÄ¦ÁCu¡£ÒÑÖªCu(¢ò)- C2O-42-ÂçºÏÎïµÄlg¦Â1=4.5£¬lg¦Â2=8.9; Cu(¢ò)-OHÂçºÏÎïµÄlg¦Â1=6.0¡£

½â£º? ?1??[CO]??[CO] ?10?0.10?10?(0.10)?10??1??[OH]?1?10?10?10 C[NH][H]2?Cu(C2O4)122?4222?2424.58.96.9?6.09.26?141.26Cu(OH)?1ÓÖNH3[NH3]??4?[NH3]?1?Ka?1?2?[NH3]?0.10mol?L?1

??Cu(NH3)?1??1[NH3]??2[NH3]2????5[NH3]5?109.35?Cu??Cu(CO)??Cu(OH)??Cu(NH)?109.362?24?3

3.¸õHºÚT(EBT)ÊÇÒ»ÖÖÓлúÈõËᣬËüµÄlgK1=11.6£¬lgK2H=6.3,Mg-EBTµÄ¡¯lgKMgIn=7.0£¬¼ÆËãÔÚPH=10.0ʱµÄlgKMgInÖµ¡£

4. ÒÑÖªµÄlg¦Â1~ lg¦Â4Ϊ2-2.0,5.0,7.0,10.0,M(OH)4µÄlg¦Â1~ lg¦Â4Ϊ-14.0,8.0,14.0,15.0¡£ÔÚŨ¶ÈΪ0.10 mol¡¤LµÄ2+

MÈÜÒºÖУ¬µÎ¼Ó°±Ë®ÖÁÈÜÒºÖеÄÓÎÀëNH3

-1

Ũ¶ÈΪ0.010 mol¡¤L£¬PH=9.0ÊÔÎÊÈÜÒºÖеÄÖ÷Òª´æÔÚÐÎʽÊÇÄÇÒ»ÖÖ£¿Å¨¶ÈΪ¶à´ó£¿Èô½«M2+Àë×ÓÈÜÒºÓÃNaOHºÍ°±Ë®µ÷½ÚÖÁPH¡Ö-1

13.0ÇÒÓÎÀ백Ũ¶ÈΪ0.010 mol¡¤L£¬ÔòÉÏÊöÈÜÒºÖеÄÖ÷Òª´æÔÚÐÎʽÊÇʲ÷᣿Ũ¶ÈÓÖΪ¶àÉÙ£¿

½â£ºÓð±Ë®µ÷½âʱ£º

??1??(0.010)??(0.010)???122

2M(NH3)12M(NH3)42+

?1[NH3]102.0?10?2.0?1???0.0083?M(NH)1223

?2[NH3]2105.0?10?4.0?2???0.083?M(NH)1223