Äê²úÊ®Íò¶Ö¶þ¼×ÃѵÄÉè¼Æ ÏÂÔØ±¾ÎÄ

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

Ŀ¼

ÕªÒª .................................................................................................................. 2 ABSTRACT ..................................................................................................... 3 1Ð÷ÂÛ ............................................................................................................... 4

1.1¸ÅÊö .................................................................................................................................................... 4 1.1.1Éè¼ÆÒÀ¾Ý ......................................................................................................................................... 4 1.1.2 Éè¼Æ¹æÄ£¼°Éè¼ÆÒªÇó .................................................................................................................... 4 1.1.3²úÆ·¹æ¸ñ¡¢ÐÔÖʼ°ÓÃ; ................................................................................................................. 4

¢å ²úÆ·¹æ¸ñ .................................................................................................................................... 4 ¢æ¶þ¼×ÃÑÐÔÖÊ .................................................................................................................................. 4 ¢ç ¶þ¼×ÃѵÄÓÃ; ............................................................................................................................ 5 1.1.4¹úÄÚÍâ¸÷ÖÖ¹¤ÒÕ¼¼Êõ×ÛÊöºÍ±È½Ï ................................................................................................. 7

¢å¶þ¼×Ãѹ¤ÒյĹúÄÚÍâÏÖ×´ .......................................................................................................... 7 ¢æ¼¼Êõ·ÖÀ༰±¾Éè¼Æ²ÉÓ÷½·¨ ...................................................................................................... 8 ¢ç¶þ¼×ÃÑ·ÖÀë¹ý³ÌÉè¼Æ ................................................................................................................ 10

2¾«ÁóËþ¹¤ÒÕÉè¼Æ ........................................................................................... 12

2.1¾«ÁóËþÎïÁϺâËã .............................................................................................................................. 12 2.1.1 »ù´¡Êý¾Ý ...................................................................................................................................... 12 2.1.2ÎïÁϺâËã ....................................................................................................................................... 12

¢åÎïÁϺâËã×éÖ¯¼òͼ .................................................................................................................... 12 ¢æ ÖÊÁ¿·ÖÊýת»»ÎªÄ¦¶û·ÖÊý ...................................................................................................... 12 ¢æ ÖÊÁ¿·ÖÊýת»»ÎªÄ¦¶û·ÖÊý ...................................................................................................... 13 ¢çÇåÎú·Ö¸î .................................................................................................................................... 13 ¢è ¾«Á󹤶ι¤ÐòÎïÁϺâËã±í ...................................................................................................... 15 2.2¾«Á󹤶ι¤ÒÕ¼ÆËã .......................................................................................................................... 16 2.2.1ÎïÁϺâË㣨¼û2.1.2£© .................................................................................................................. 16 2.2.2²Ù×÷Ìõ¼þµÄÈ·¶¨ ........................................................................................................................... 16 2.3¾«ÁóËþÉ豸¼ÆËã .............................................................................................................................. 18 2.3.1»ù´¡Êý¾Ý ....................................................................................................................................... 18 2.3.2Ëþ°åÊýµÄÈ·¶¨ ............................................................................................................................... 22 2.3.3¾«ÁóËþÖ÷Òª³ß´ç¼ÆËã ................................................................................................................... 24 2.3.4Ëþ°å½á¹¹Éè¼Æ ............................................................................................................................... 26 2.4¸¡·§ËþÌáÁï¶ÎÓ뾫Áó¶ÎÉè¼Æ²ÎÊý»ã×Ü .......................................................................................... 28

1

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ

ÕªÒª

½üÄêÀ´£¬¶þ¼×ÃѳÉΪ¹ú¼ÊʯÓÍÌæ´ú;¾¶ÓëÐÂÐͶþ´ÎÄÜÔ´µÄÈȵã¿ÎÌ⣬ÒýÆð¸÷¹ú¹Ø×¢ÓëÖØÊÓ¡£

¶þ¼×ÃѵÄÖÆ±¸Ö÷ÒªÓм״¼ÍÑË®·¨ºÍºÏ³ÉÆøÒ»²½·¨Á½ÖÖ¡£Ó봫ͳµÄ¼×´¼ºÏ³É¶þ¼×ÃÑÏà±È£¬Ò»²½·¨ºÏ³É¶þ¼×Ãѹ¤ÒÕ¾­¼Ã¸ü¼ÓºÏÀí£¬ÔÚÊг¡¸ü¾ßÓоºÕùÁ¦£¬ÕýÔÚ×ßÏò¹¤Òµ»¯¡£Ä¿Ç°£¬ÖÆÈ¡¶þ¼×ÃѵÄ×îм¼ÊõÊÇ´ÓºÏ³ÉÆøÖ±½ÓÖÆÈ¡£¬Ïà±È½Ï¼×´¼ÍÑË®ÖÆ¶þ¼×ÃѶøÑÔ£¬Ò»²½·¨ºÏ³É¶þ¼×ÃÑÒòΪÌåϵ´æÔÚÓÐδ·´Ó¦Íê³ÉµÄºÏ³ÉÆøÒÔ¼°¶þÑõ»¯Ì¼£¬ÒªµÃµ½´¿¶È½Ï¸ßµÄ¶þ¼×ÃÑ£¬·ÖÀë¹ý³Ì±È½Ï¸´ÔÓ¡£¿ª·¢ÖеķÖÀ빤ÒÕÖ÷Òª²ÉÓÃÎüÊպ;«ÁóµÈ»¯¹¤µ¥Ôª²Ù×÷¹ý³ÌµÃµ½´¿¶È½Ï¸ßµÄ¶þ¼×ÃѲúÆ·¡£±¾Éè¼ÆÖ÷ÒªÕë¶Ô·ÖÀëÖеľ«Áó¹¤Ðò½øÐй¤ÒÕÉè¼Æ£¬·ÖÀë¶þ¼×ÃÑ ¡¢¼×´¼ºÍË®ÈýÔªÌåϵ¡£¾«ÁóËþ²ÉÓø¡·¨Ëþ£¬Ëþ¶¥ÀäÄýÆ÷×°ÖòÉÓÃÈ«ÄýÆ÷£¬ÓÃÀ´×¼È·¿ØÖÆ»ØÁ÷±È£»Ëþµ×²ÉÓÃË®ÕôÆû¼ÓÈÈ£¬ÒÔÌṩ×ã¹»µÄÈÈÁ¿¡£Í¨¹ý¼ÆËãµÃ³öÀíÂÛËþ°åÊý£¬ËþЧÂÊ£¬É¸¿×Êý¡£Í¨¹ýɸ°åµÄÁ÷ÌåÁ¦Ñ§ÑéË㣬֤Ã÷¸÷Ö¸±êÊý¾Ý¾ù·ûºÏ±ê×¼¡£ÒÔ±£Ö¤¾«Áó¹ý³ÌµÄ˳Àû½øÐв¢Ê¹Ð§Âʾ¡¿ÉÄܵÄÌá¸ß¡£

¹Ø¼ü´Ê£º ¶þ¼×ÃÑ ·ÖÀë ÈýÔªÌåϵ ¾«Áó

2

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

Annual output of 10,000 tons of dimethyl ether distillation

Section in the design of sepration device

ABSTRACT

In recent years, DME has become an alternative channel of international oil and new secondary energy and hot topics, That aroused national concern and attention.

Preparation of dimethyl ether mainly methanol dchydration and One-step synethesis. With the tradional methanol synethesis compared to synethesis of dimethyl ether,one-step synethesis of dimethyl ether process more rational economy, more competive in the market and it is moving towards industrialiazation. Curently , synethesis gas to dimethyl ether is the latest technology preparation of dimethyl ether. Compared with methanol dchydration , system of direct synthesis of DME as the existence of unreacted synthesis gas and carbon dioxide finished.If it want to get high purity dimethyl ether, more complicated separation process. Developed mainly in the separation process such as chemical absorption and distillation unit operation in the process of dimethylethyl ether with higher purity product.This design aimed at separating the distillation process for process design. Separation of DME , methanol and water ternary system. Design of distillation towers used valve. Use the whole top of the tower condenser cooling device used to provide sufficient heat.Obtained by calculating the number of theoretical plate design and calculation of process dimensions derived column diametet, the effective tower, sieve number. Checking through the sieve of fluid mechanics, to prove that the indicator data are in line with standards to ensure the smooth progress of distillation process and to improve efficiency as much as possible.

Keywords:DME separate ternary system distillation

3

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

1Ð÷ÂÛ

1.1¸ÅÊö 1.1.1Éè¼ÆÒÀ¾Ý

¸ù¾Ý¾£³þÀí¹¤Ñ§Ôº»¯¹¤ÓëҩѧԺÏ´ïµÄÉè¼ÆÈÎÎñÊ飬ģÄâÏÖÓеĽ¬Ì¬´²Ò»²½·¨£¨¼´ºÏ³ÉÆøÒ»²½·¨£©¶þ¼×ÃѺϳɲúÒµ»¯¼¼Êõ£¬¶Ô¶þ¼×ÃÑ·ÖÀë×°ÖÃÖеľ«Á󹤶νøÐÐÉè¼Æ¡£

1.1.2 Éè¼Æ¹æÄ£¼°Éè¼ÆÒªÇó

¢ÙÉè¼Æ¹æÄ£: Äê²ú10.0Íò¶Ö¶þ¼×ÃÑ·ÖÀë×°ÖÃ(ºÏ³ÉÆøÒ»²½·¨)£¬Éè¼Æ¸Ã·ÖÀë×°ÖÃÖо«Á󹤶ι¤ÒÕ¾«Á󣬾«Áó×°ÖòÉÓø¡·§Ëþ¡£Ò»Äê°´330¸ö¹¤×÷ÈÕ£¬Ã¿¸ö¹¤×÷ÈÕ°´24Сʱ¼ÆË㣻 ¢Ú²úÆ·ÒªÇ󣺶þ¼×ÃÑ¡Ý99%£»

¢Û¶þ¼×ÃѸ÷·ÖÀë¹ý³ÌÖеÄ×é³ÉÈçÏ£º£¨±íÖÐÊý¾Ý¾ùΪÖÊÁ¿·ÖÊý£© ×é³É H2 ¶èÐÔÆøÌå CO CO2 CH4 DME CH3OH H2O ·´Ó¦ºóÈëÀäÄýÆ÷µÄÆøÌå 0.1797 0.0059 0.0929 0.1101 0.1711 0.1526 0.0217 0.2660 ÎüÊÕËþÈë¿Ú ¾«ÁóËþ½øÁÏ ¾«ÁóËþËþ¶¥ 0.2870 0.0094 0.1483 0.1709 0.2730 0.1097 0.0004 0.0013 0 0 0 0 0 0.0309 0.0043 0.9618 0 0 0 0 0 0.999 0.001 0 ¾«ÁóËþËþµ× 0 0 0 0 0 8.14¡Á10 0.007819 0.9921 -51.1.3²úÆ·¹æ¸ñ¡¢ÐÔÖʼ°ÓÃ;

¢å ²úÆ·¹æ¸ñ£º¶þ¼×ÃÑ¡Ý99%(ÖÊÁ¿º¬Á¿) ¢æ¶þ¼×ÃÑÐÔÖÊ

ÎïÀíÐÔÖÊ£º¶þ¼×ÃÑÒà³Æ¼×ÃÑ£¬Ó¢ÎÄdimethylether,Ó¢ÎÄËõдDME,»¯Ñ§·Ö×Óʽ(CH30CH3 ),

4

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

·Ö×ÓÁ¿Îª46.07£¬ÊÇÖØÒªµÄ¼×´¼ÑÜÉúÎ·Ðµã-24¡æ£¬Äý¹Ìµã-140¡æ¡£¶þ¼×ÃÑÊÇÒ»ÖÖº¬ÑõÓлúÎÈÜÓÚË®£¬ÔÚ´óÆøÖпÉÒÔ½µ½â£¬ÊôÓÚ»·¾³ÓѺÃÐÍÎïÖÊ¡£¶þ¼×ÃÑÔÚ³£ÎÂÏÂÊÇÒ»ÖÖÎÞÉ«ÆøÌ壬¾ßÓÐÇá΢µÄÃÑÏãζ¡£¶þ¼×ÃÑÎÞ¸¯Ê´ÐÔ¡¢ÎÞ¶¾¡¢ÔÚ¿ÕÆøÖг¤ÆÚ±©Â¶²»»áÐγɹýÑõ»¯ÎȼÉÕʱ»ðÑæÂÔ´ø¹âÁÁ¡£

¶þ¼×ÃѵÄΣÏÕÌØÐÔ£º¶þ¼×ÃÑΪÒ×È¼ÆøÌå¡£Óë¿ÕÆø»ìºÏÄÜÐγɱ¬Õ¨ÐÔ»ìºÏÎï¡£½Ó´¥ÈÈ¡¢»ðÐÇ¡¢»ðÑæ»òÑõ»¯¼ÁÒ×ȼÉÕ±¬Õ¨¡£½Ó´¥¿ÕÆø»òÔÚ¹âÕÕÌõ¼þÏ¿ÉÉú³É¾ßÓÐDZÔÚ±¬Õ¨Î£ÏÕÐԵĹýÑõ»¯Îï¡£

ÆøÌå±È¿ÕÆøÖØ£¬ÄÜÔڽϵʹ¦À©É¢µ½Ï൱ԶµÄµØ·½£¬ÓöÃ÷»ð»áÒý×Å»ØÈ¼¡£ÈôÓö¸ßÈÈ£¬ÈÝÆ÷ÄÚѹÔö´ó£¬ÓпªÁѺϱ¬Õ¨µÄΣÏÕ¡£

¶þ¼×Ãѵ;ÐÔ£º¶þ¼×ÃÑΪÈõÂé×í¼Á£¬¶ÔºôÎüµÀÓÐÇá΢µÄ´Ì¼¤×÷Ó㬳¤ÆÚ½Ó´¥Æ¤·ô·¢ºì¡¢Ë®Öס¢Éúð塣Ũ¶ÈΪ7.5£¥£¨Ìå»ý£©Ê±£¬ÎüÈë12·ÖÖÓºó½ö×Ըв»ÊÊ¡£Å¨¶Èµ½8.2£¥£¨Ìå»ý£©Ê±£¬¾­21·ÖÖÓÒýÆð¹©¸øÊ§µ÷£¬²úÉúÊÓ¾õÕϰ­£¬30·ÖÖÓºóÇá¶ÈÂé×í£¬ÑªÒºÁ÷ÏòÍ·²¿£¬Å¨¶ÈΪ14£¥£¨Ìå»ý£©Ê±£¬¾­23·ÖÖÓÒýÆðÔ˶¯¹¤¼Ãʧµ÷¼°Âé×í£¬¾­26·ÖÖÓʧȥ֪¾õ£¬Æ¤·ô½Ó´¥¼×ÃÑʱÒ×¶³ÉË¡£¿ÕÆøÖÐÔÊÐíŨ¶ÈΪ400ppm¡£¶þ¼×ÃѵÄÎïÀíÐÔÖʼû±í1-1

¢ç ¶þ¼×ÃѵÄÓÃ;£º Ìæ´úÂÈ·úÌþ×öÆøÎí¼Á

Ëæ×ÅÊÀ½ç¸÷¹úµÄ»·±£ÒâʶÈÕÒæÔöÇ¿£¬ÒÔǰ×÷ÎªÆøÈܹ¤ÒµÖÐÆøÎí¼ÁÕýÖð²½±»ÆäËüÎÞÎïÖÊËùÌæ´ú¡£ ¢Å ÓÃ×÷ÖÆÀä¼ÁºÍ·¢ÅݼÁ

ÓÉÓÚDMEµÄ·Ðµã½ÏµÍ£¬Æû»¯ÈÈ½Ï´ó£¬Æû»¯Ð§¹ûºÃ£¬ÆäÀäÄýºÍÕô·¢ÌØÐÔ½Ó½ü·úÂÈÌþ£¬Òò´ËDME×÷ÖÆÀä¼Á·Ç³£ÓÐǰ;¡£¹úÄÚÍâÕýÔÚ»ý¼«¿ª·¢ËüÔÚ±ùÏä¡¢¿Õµ÷¡¢Ê³Æ·±£ÏʼÁµÈ·½ÃæµÄÓ¦Óã¬ÒÔ´úÌæ·úÂÈÌþ£¬ÓÈÆäÊÇ·úÀû°º¡£¹ØÓÚDME×÷·¢ÅݼÁ£¬¹úÍâÒÑÏà¼Ì¿ª·¢³öÀûÓÃDME×÷¾Û±½ÒÒÏ©¡¢¾Û°±»ù¼×ËáÒÒõ¥¡¢ÈÈËܾÛõ¥ÅÝÄ­µÄ·¢ÅݼÁ£¬·¢ÅݺóµÄ²úÆ·£¬¿×µÄ´óС¾ùÔÈ£¬ÈáÈÍÐÔ¡¢ÄÍѹÐÔ¡¢¿¹ÁÑÐԵȶ¼ÓÐËùÇ¿µ÷¡£ ¢Æ DMEÓÃ×÷ȼÁÏ

ÓÉÓÚDME¾ßÓÐÒº»¯Ê¯ÓÍÆøÏàËÆµÄÕôÆûѹ£¬ÔÚµÍѹÏÂDME±äΪҺÌ壬ÔÚ³£Î¡¢³£

5

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

ѹÏÂÎªÆøÌ¬£¬Ò×ȼ¡¢¶¾ÐԺܵͣ¬²¢ÇÒDMEµÄÊ®ÁùÍéÖµ£¨Ô¼55±¶£©¸ß£¬×÷ΪҺ»¯Ê¯ÓÍÆøºÍ²ñÓÍÆû³µµÄ´ýÓÃÌõ¼þÒѾ­³ÉÊì¡£ÓÉÓÚËüÊÇÒ»ÖÖÓÅÁ¼µÄÇå½àÄÜÔ´£¬ÒÑÈÕÒæÊܵ½¹úÄÚÍâµÄ¹ã·º¹Ø×¢¡£ÔÚδÀ´Ê®ÄêÀDME×÷ΪȼÁϵÄÓ¦Óý«ÄÑÒÔ¹ÀÁ¿µÄDZÔÚÊг¡£¬ÆäÓ¦ÓÃǰ¾°Ê®·ÖÀÖ¹Û¡£¿É¹ã·ºÓÃÓÚÃñÓÃÇå½àȼÁÏ¡¢Æû³µ·¢¶¯»úȼÁÏ¡¢´¼ÃÑȼÁÏ¡£ ¢Ç DMEÓÃ×÷»¯¹¤Ô­ÁÏ

DME ×÷ΪһÖÖÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬¿ÉÒԺϳɶàÖÖ»¯Ñ§Æ·¼°²ÎÓë¶àÖÖ»¯Ñ§·´Ó¦£ºÓëSO3·´Ó¦¿ÉÖÆµÄÁòËá¶þ¼×õ¥£ºÓëHCL·´Ó¦¿ÉºÏ³ÉÍé»ù±»¯ÎÓë±½°··´Ó¦¿ÉºÏ³ÉN,N-¶þ¼×»ù±½°·£»ÓëCO·´Ó¦¿ÉôÊ»ùºÏ³ÉÒÒËá¼×õ¥¡¢´×ôû£¬Ë®½âºóÉú³ÉÒÒË᣻ÓëºÏ³ÉÆøÔÚ´ß»¯¼Á´æÔÚÏ·´Ó¦Éú³ÉÒÒËáÒÒÏ©£»Ñõ»¯ôÊ»¯ÖÆÌ¼»¯¶þ¼×õ¥£»ÓëH2S·´Ó¦ÖƱ¸¶þ¼×»ùÁòÃÑ¡£´ËÍ⣬ÀûÓÃDME»¹¿ÉÒԺϳɵÍÏ©Ìþ¡¢¼×È©ºÍÓлú¹è»¯ºÏÎ¶þ¼×ÃÑ»¹¿ÉÒԺϳÉÇâÇèËá¡¢¼×È©µÈÖØÒª»¯Ñ§Æ·¡£¶þ¼×ÃÑÓë»·ÑõÒÒÍé·´Ó¦£¬ÔÚÂ±ËØ½ðÊô»¯ºÏÎïºÍH3BO3µÄ´ß»¯×÷ÓÃÏ£¬ÔÚ50¡æ~55¡æÊ±Éú³ÉÒÒ¶þ´¼¶þ¼×ÃÑ¡¢¶þÒÒ¶þ´¼¶þ¼×ÃÑ¡¢ÈýÒÒ¶þ´¼¶þ¼×ÃÑ¡¢ËÄÒÒ¶þ´¼¶þ¼×ÃѵĻìºÏÎÆäÖ÷Òª²úÎïÒÒ¶þ´¼¶þ¼×ÃÑÊÇÖØÒªÈܼÁºÍÓлúºÏ³ÉµÄÖмäÌå¡£

Ŀǰ£¬È«Çò¶þ¼×ÃÑ×ÜÉú²úÄÜÁ¦Ô¼Îª21Íò¶Ö¨Ma£¬²úÁ¿16Íò¶Ö¨Ma×óÓÒ£¬±í1-1ΪÊÀ½ç¶þ¼×ÃÑÖ÷ÒªÉú²ú³§¼Ò¼°²úÆ·Á¿¡£ÎÒ¹ú¶þ¼×ÃÑ×ÜÉú²úÄÜÁ¦Ô¼Îª1.2Íòt¨Ma£¬²úÁ¿Ô¼0.8Íòt¨Ma¡£±í1-2ΪÎÒ¹ú¶þ¼×ÃÑÖ÷ÒªÉú²ú³§¼Ò¼°²úÁ¿¡£

¾ÝÊг¡µ÷²é¹úÄÚ¶þ¼×ÃÑÐèÇóÔ¶Ô¶³¬¹ý¹©¸øÁ¿£¬Ä¿Ç°¹úÄÚ½öÆøÎí¼ÁÒ»ÏîÐèÇóÁ¿´ïµ½1.5~1.8Íò¶Ö¨MÄ꣬¶ø¸ß´¿¶ÈµÄ¶þ¼×ÃÑ»¹ÒÀÀµ½ø¿Ú¡£±í1-3Ϊ2005Äêµ½2010ÎÒ¹ú¶Ô¶þ¼×ÃѵÄÊг¡ÐèÇóÔ¤²â£¬¿É¼û£¬¶þ¼×ÃÑÊг¡Ó¦ÓÃǰ¾°¹ãÀ«£¬Òò´Ë¶Ô¶þ¼×ÃѵÄÉú²ú¹¤ÒÕ½øÐÐÑо¿ºÜÓбØÒª¡£

±í1-2ÊÀ½ç¶þ¼×ÃÑÖ÷ÒªÉú²ú³§¼Ò¼°²úÁ¿

6

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

±í1-3ÎÒ¹ú¶þ¼×ÃÑÖ÷ÒªÉú²ú³§¼ÒºÍ²úÁ¿

±í1-4ÎÒ¹ú¶Ô¶þ¼×ÃѵÄÊг¡ÐèÇóÔ¤²â

1.1.4¹úÄÚÍâ¸÷ÖÖ¹¤ÒÕ¼¼Êõ×ÛÊöºÍ±È½Ï

¢å¶þ¼×Ãѹ¤ÒյĹúÄÚÍâÏÖ×´

ÎÒ¹ú90Äê´úǰºó¿ªÊ¼ÆøÏà¼×´¼·¨£¨Á½²½·¨£©Éú²ú¶þ¼×Ãѹ¤ÒÕ¼¼Êõ¼°´ß»¯¼ÁµÄ¿ª·¢£¬ºÜ¿ì½¨Á¢ÆðÁ˹¤ÒµÉú²ú×°Ö᣽üÄêÀ´£¬Ëæ×Ŷþ¼×Ãѽ¨ÉèÈȳ±µÄÐËÆð£¬ÎÒ¹úÁ½²½·¨¶þ¼×Ãѹ¤ÒÕ¼¼ÊõÓÐÁ˽øÒ»²½µÄ·¢Õ¹£¬¹¤ÒÕ¼¼ÊõÒѽӽü»ò´ïµ½¹úÍâÏȽøË®Æ½¡£

ɽ¶«¾ÃÌ©»¯¹¤¿Æ¼¼¹É·ÝÓÐÏÞ¹«Ë¾£¨Ô­ÁÙÒʳÃ÷»¯¹¤ÓÐÏÞ¹«Ë¾£©¿ª·¢³É¹¦Á˾ßÓÐ×ÔÖ÷֪ʶ²úȨµÄÒºÏà·¨¸´ºÏËáÍÑË®´ß»¯Éú²ú¶þ¼×Ãѹ¤ÒÕ£¬ÒѾ­½¨³ÉÁË5000¶Ö/ÄêÉú²ú×°Ö㬾­Ò»Äê¶àµÄÉú²úʵ¼ùÖ¤Ã÷£¬¸Ã¼¼Êõ³ÉÊì¿É¿¿¡£¸Ã¹«Ë¾µÄµÚ¶þÌ×3Íò¶Ö/Äê×°ÖÃÒ²½«Í¶²ú¡£É½¶«¾ÃÌ©¶þ¼×Ãѹ¤ÒÕ¼¼ÊõÒѾ­Í¨¹ýÁËɽ¶«Ê¡¿Æ¼¼Ìü×éÖ¯µÄ¼ø¶¨£¬±»È϶¨ÎªÒÑ´ï¹ú¼Êˮƽ¡£ÌرðÊÇÒºÏà·¨¸´ºÏËáÍÑË®´ß»¯¼ÁµÄÑÐÖÆºÍÀäÄý·ÖÀë¼¼Êõ£¬Õë¶ÔÐԵؿ˷þÁËÒ»²½·¨ºÏ³ÉºÍÆøÏàÍÑË®ÖÐÌá´¿³É±¾¸ß¡¢Í¶×Ê´óµÄȱµã£¬Ê¹·´Ó¦ºÍÍÑË®Äܹ»Á¬Ðø½øÐУ¬¼õÉÙÁËÉ豸¸¯Ê´ºÍÉ豸Ͷ×Ê£¬×Ü»ØÊÕÂÊ´ïµ½99.5£¥ÒÔÉÏ£¬²úÆ·´¿¶È²»Ð¡ÓÚ99.9£¥£¬Éú²ú³É±¾Ò²½ÏÆøÏà·¨ÓнϴóµÄ½µµÍ¡£

2003Äê8ÔÂÓÉãòÌ컯ÓëÈÕ±¾¶«Ñ󹤳̹«Ë¾ºÏ×÷¿ª·¢µÄÁ½²½·¨¶þ¼×ÃÑÍò¶Ö¼¶Éú²ú×°ÖÃÊÔ³µ³É¹¦¡£¸Ã×°Öù¤ÒÕÁ÷³ÌºÏÀí£¬²Ù×÷Ìõ¼þÓÅ»¯£¬¾ßÓвúÆ·´¿¶È¸ß¡¢ÎïºÄµÍ¡¢Äܺĵ͵ÄÌØµã£¬ÔÚ¹¤ÒÕˮƽ¡¢²úÆ·ÖÊÁ¿ºÍÉ豸Ӳ¼þ×Ô¶¯»¯²Ù×÷µÈ·½Ãæ¾ù´¦ÓÚ¹úÄÚÏȽøË®Æ½¡£

º¼ÖÝ´óѧ²ÉÓÃ×ÔÖÆµÄ¶þ¼×ÃÑ´ß»¯¼Á£¬ÀûÓúϳɰ±³§ÏÖÓеİëË®ÃºÆø£¬ÔÚÒ»¶¨·´Ó¦Î¶ȡ¢

7

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

ѹÁ¦ºÍ¿ÕËÙÏÂÒ»²½ÆøÏàºÏ³É¶þ¼×ÃÑ¡£COµ¥³Ìת»¯ÂÊ´ïµ½60%¡«83%£¬Ñ¡ÔñÐÔ´ï95%¡£¸Ã¼¼ÊõÏÖËÈÔÚºþ±±ÌïÁ¦¹«Ë¾½¨³ÉÁËÄê²ú1500¶Ö¶þ¼×ÃѵĹ¤Òµ»¯×°Ö᣸Ã×°ÖüȿÉÉú²ú´¼ÃÑȼÁÏ£¬ÓÖ¿ÉÉú²ú99.9%ÒÔÉϵĸߴ¿¶þ¼×ÃÑ£¬COת»¯ÂÊ70%-80%¡£ÕâÊǹúÄÚµÚÒ»Ì×Ö±½ÓÓÉºÏ³ÉÆøÒ»²½·¨Éú²ú¸ß´¿¶þ¼×ÃѵĹ¤Òµ»¯Éú²ú×°Öá£

¶ÔÓÚÁ½²½·¨¶þ¼×Ãѹ¤ÒÕ¼¼Êõ£¬ÎÞÂÛÊÇÆøÏà·¨»¹ÊÇÒºÏà·¨£¬¹úÄÚ¼¼Êõ¾ùÒѾ­´ïµ½ÏȽø¡¢³ÉÊì¿É¿¿µÄˮƽ£¬ÍêÈ«ÓÐÌõ¼þ½¨Éè´óÐÍÉú²ú×°Öá£ÓɹúÄÚ¿ª·¢µÄºÏ³ÉÆøÒ»²½ÆøÏà·¨ÖÆ¶þ¼×ÃѼ¼Êõ»ù±¾³ÉÊ죬²¢Òѽ¨³Éǧ¶Ö¼¶×°Öᣵ«¶ÔÓÚ½¨Éè´óÐͶþ¼×ÃÑ×°Ö㬹úÄÚ¼¼ÊõÉÐÐèʵ¼ùÑéÖ¤¡£

¢æ¼¼Êõ·ÖÀ༰±¾Éè¼Æ²ÉÓ÷½·¨

¢Ù·ÖÀà

ĿǰºÏ³ÉDME¿É·ÖΪ£º1.ÒºÏà¼×´¼ÍÑË®·¨¡¢2.ÆøÏà¼×´¼ÍÑË®·¨¡¢3.ºÏ³ÉÆøÒ»²½·¨¡¢4.CO2

¼ÓÇâÖ±½ÓºÏ³É·¨¡¢5.´ß»¯ÕôÁ󷨡£ÆäÖÐǰÁ½ÖÖ·½·¨±È½Ï³ÉÊ죬ºóÈýÖÖ·½·¨Õý´¦ÓÚÑо¿ºÍ¹¤Òµ·Å´ó½×¶Î¡£

¢Ú±¾Éè¼Æ²ÉÓÃµÄºÏ³ÉÆøÒ»²½·¨¸ÅÊö

ǰÊö¾ßÌå·½·¨´Ë´¦²»×öÏêÊö£¬½ö¶Ô±¾Éè¼Æ²ÉÓÃºÏ³ÉÆøÒ»²½·¨ÉÔ¼Ó½éÉÜ£ººÏ³ÉÆøÒ»²½·¨ÖÆDMEÊÇÔںϳɼ״¼¼¼ÊõµÄ»ù´¡ÉÏ·¢Õ¹ÆðÀ´µÄ£¬ÓÉºÏ³ÉÆø¾­½«ÒºÌ¬´²·´Ó¦Æ÷Ò»²½ºÏ³ÉDME,²ÉÓþßÓм״¼ºÏ³ÉºÍ¼×´¼ÍÑË®×é·ÖµÄË«¹¦ÄÜ´ß»¯¼Á¡£Òò´Ë£¬¼×´¼ºÏ³É´ß»¯¼ÁºÍ¼×´¼ÍÑË®´ß»¯¼ÁµÄ±ÈÀý¶ÔDMEÉú³ÉËٶȺÍÑ¡ÔñÐÔÓкܴóµÄÓ°Ï죬ÊÇÆäÑо¿Öص㡣Æä¹ý³ÌµÄÖ÷Òª·´Ó¦Îª£º

¼×´¼ºÏ³É·´Ó¦£¨COÇ⻯£©

CO + 2H2 = CH3OH + 90.14 kJ/mol (1)

Ë®ÃºÆø±ä»»·´Ó¦

CO + H2O = CO2 + H2 + 40.19 kJ/mol (2)

¼×´¼ÍÑË®·´Ó¦

2CH3OH = CH3OCH3 + H2O + 23.14 kJ/mol (3) ¼×´¼ºÏ³É£¨CO2Ç⻯×÷Óã©

CO2 + 3H2 = CH3OH + H2O + 49.4 kJ/mol £¨4£© ×Ü·´Ó¦

3CO + 3H2 = CH3OCH3 + CO2 + 258.12 kJ/mol £¨5£©

Ôڸ÷´Ó¦ÌåϵÖУ¬ÓÉÓÚ¼×´¼ºÏ³É·´Ó¦ºÍÍÑË®·´Ó¦Í¬Ê±½øÐУ¬Ê¹µÃ¼×´¼Ò»¾­

Éú³É¼´±»×ª»¯ÎªDME£¬´Ó¶ø´òÆÆÁ˼״¼ºÏ³É·´Ó¦µÄÈÈÁ¦Ñ§Æ½ºâÏÞÖÆ£¬Ê¹COת»¯ ÂʱÈÁ½²½·´Ó¦¹ý³ÌÖе¥¶À¼×´¼ºÏ³É·´Ó¦ÓÐÏÔÖøÌá¸ß¡£

8

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

¢ÛÓëÆäÓà·½·¨µÄ±È½Ï£º

×÷Ϊ´¿´âµÄDMEÉú²ú×°ÖöøÑÔ£¬±í1-5ÁгöÁË5ÖÖ²»Í¬¹¤ÒÕµÄÉú²ú¼¼Êõ¾­¼ÃÖ¸±ê¡£Óɱí1¡ª5¿ÉÒÔ¿´³ö£¬ÆûÏà¼×´¼ÍÑË®·¨ÖÆDME,Ïà¶ÔÒºÏà·¨£¬ÆûÏà·¨¾ßÓвÙ×÷¼òµ¥£¬×Ô¶¯»¯³Ì¶È½Ï¸ß£¬ÉÙÁ¿·ÏË®·ÏÆøÅÅ·Å£¬ÅÅ·ÅÎïµÍÓÚ¹ú¼Ò¹æ¶¨µÄ±ê×¼£¬DMEÑ¡ÔñÐԺͲúÆ·ÖÊÁ¿¸ßµÈÓŵ㡣ͬʱ¸Ã·¨Ò²ÊǹúÄÚÍâÉú²úDMEµÄÖ÷Òª·½·¨¡£

±í1-5¶þ¼×ÃѸ÷Öֺϳɷ¨¾­¼Ã¼¼Êõ±È½Ï

Óŵ㣺ÓÉºÏ³ÉÆøÒ»²½·¨ÖÆDMEµÄÉú²ú¼¼Êõ³É±¾Ô¶½ÏÁòËá·¨ºÍ¼×´¼ÍÑË®·¨ÎªµÍ£¬Òò¶ø¾ßÓÐÃ÷ÏԵľºÕùÐÔ¡£¾ßÌåÀ´Ëµ£¬Óë¼×´¼ÍÑË®·¨Ïà±È£¬¾ßÓÐÁ÷³Ì¶Ì¡¢Í¶×ÊÊ¡¡¢Äܺĵ͵ÈÓŵ㣬¶øÇÒ¿É»ñµÃ½Ï¸ßµÄµ¥³Ìת»¯ÂÊ¡£ºÏ³ÉÆøÒ»²½·¨ÏÖ¶à²ÉÓý¬Ì¬´²·´Ó¦Æ÷£¬Æä½á¹¹¼òµ¥¼òµ¥£¬±ãÓڷųö·´Ó¦ÈÈ£¬Ò×ʵÏÖºãβÙ×÷¡£Ëü¿ÉÖ±½ÓÀûÓÃCOº¬Á¿¸ßµÄú»ùºÏ³ÉÆø£¬»¹¿ÉÒÔÔÚÏßÐ¶ÔØ´ß»¯¼Á¡£Òò´Ë£¬½«ÒºÌ¬ºÏ³ÉÆø·¨ÖÆDME¾ßÓÐÓÕÈËǰ¾°£¬½«ÊÇú̿½à¾»ÀûÓõÄÖØÒªÍ¾¾¶Ö®Ò»¡£ºÏ³ÉÆø·¨ËùÓÃµÄºÏ³ÉÆø¿ÉÓÉú¡¢Ê¯ÓÍ¡¢ÖØÓÍ¡¢ÔüÓÍÆø»¯¼°ÌìÈ»Æø×ª»¯¶øµÃ£¬Ô­ÁϾ­¼ÃÒ׵ã¬Òò¶ø¸Ã¹¤ÒÕ¿ÉÓÃÓÚ»¯·ÊºÍ¼×´¼×°ÖÃÊʵ±¸ÄÔìºóÉú²úDME,Ò×Ðγɽϴó¹æÄ£Éú²ú£»Ò²¿É²ÉÓôӻ¯·ÊºÍ¼×´¼Éú²ú×°ÖòàÏß³éµÃºÏ³ÉÆøµÄ·½·¨£¬Êʵ±Ôö¼ÓÉÙÁ¿Æø»¯ÄÜÁ¦£¬»ò¼õÉÙ¼×´¼ºÍ°±µÄµÄÉú²úÄÜÁ¦£¬ÓÃÒÔÉú²úDME.

ȱµã£ºµ«Ïà¶ÔÆäËüÁ½Àà·½·¨£¬Ä¿Ç°¸Ã·½·¨Õý´¦ÓÚ¹¤Òµ·Å´ó½×¶Î£¬¹æÄ£½ÏС£¬ÁíÍ⣬Ëü¶Ô´ß»¯¼Á¡¢·´Ó¦Ñ¹Á¦ÒªÇó½Ï¸ß£¬²úÆ·µÄ·ÖÀë´¿¶ÈµÍ£¬¶þ¼×ÃÑÑ¡ÔñÐԵͣ¬Õâ¶¼ÊÇÎÊÌâ¡£

¢ÜÒ»²½·¨Ñо¿¸Å¿ö

½üÄêÀ´£¬ÎÒ¹úÔÚºÏ³ÉÆøÒ»²½·¨Öƶþ¼×ÃÑ·½ÃæµÄ¼¼Êõ¿ª·¢Ò²ºÜ»ý¼«£¬¶øÇÒһЩ¿ÆÑÐÔºËù

ºÍ´óѧ¶¼È¡µÃÁ˽ϴó½øÕ¹¡£

À¼»¯Ñо¿Ôº¡¢À¼»¯»¯·Ê³§ÓëÀ¼ÖÝ»¯ÎïËù¹²Í¬¿ªÕ¹ÁËºÏ³ÉÆø·¨Öƶþ¼×ÃѵÄ5mLСÊÔÑо¿£¬ÖØµã½øÐй¤ÒÕ¹ý³ÌÑо¿¡¢´ß»¯¼ÁÖÆ±¸¼°Æä»îÐÔ¡¢ÊÙÃüµÄ¿¼²ì¡£ÊÔÑéÈ¡µÃÁ¼ºÃ½á¹û£ºCOת»¯ÂÊ>85%£»Ñ¡ÔñÐÔ>99%¡£Á½´Î³¤ÖÜÆÚ(500h¡¢1000h)ÊÔÑé±íÃ÷£ºÑÐÖÆµÄ´ß»¯¼ÁÔÚ¹¤ÒµÔ­ÁÏºÏ³ÉÆøÖÐÓÐÁ¼ºÃµÄÎȶ¨ÐÔ£»¶þ¼×ÃѶÔÓлúÎïµÄÑ¡ÔñÐÔ>97%£»COת»¯ÂÊ>75%£»¶þ¼×ÃѲúÆ·´¿¶È>99.5%£»¶þ¼×ÃÑ×ÜÊÕÂÊΪ98.45%¡£

9

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

ÖпÆÔº´óÁ¬»¯ÎïËù²ÉÓø´ºÏ´ß»¯¼ÁÌåϵ¶ÔºÏ³ÉÆøÖ±½ÓÖÆ¶þ¼×ÃѽøÐÐÁËϵͳÑо¿£¬É¸Ñ¡³öSD219-¢ñ¡¢SD219-¢ò¼°SD219-¢óÐÍ´ß»¯¼Á£¬¾ù±íÏÖ³ö½Ï¼ÑµÄ´ß»¯ÐÔÄÜ£¬COת»¯ÂÊ´ïµ½90%£¬Éú³ÉµÄ¶þ¼×ÃÑÔÚº¬ÑõÓлúÎïÖеÄÑ¡ÔñÐÔ½Ó½ü100%¡£

Ç廪´óѧҲ½øÐÐÁËÒ»²½·¨¶þ¼×ÃÑÑо¿£¬ÔÚ½¬Ì¬´²·´Ó¦Æ÷ÉÏ£¬²ÉÓÃLP+Al2O3Ë«¹¦ÄÜ´ß»¯¼Á£¬ÔÚ260-290¡æ£¬4-6MPaµÄÌõ¼þÏ£¬COµ¥³Ìת»¯ÂÊ´ïµ½55%¡«65%£¬¶þ¼×ÃѵÄÑ¡ÔñÐÔΪ90-94%¡£

Ŀǰ£¬¹úÄÚµÄÕã½­´óѧ¡¢É½Î÷ú»¯Ëù¡¢Î÷ÄÏ»¯¹¤Ñо¿Ôº¡¢»ª¶«Àí¹¤´óѧµÈµ¥Î»Ò²¶¼ÖÂÁ¦ÓÚºÏ³ÉÆøÒ»²½·¨Öƶþ¼×ÃѵÄÑо¿¹¤×÷¡£

º¼ÖÝ´óѧ²ÉÓÃ×ÔÖÆµÄ¶þ¼×ÃÑ´ß»¯¼Á£¬ÀûÓúϳɰ±³§ÏÖÓеİëË®ÃºÆø£¬ÔÚÒ»¶¨·´Ó¦Î¶ȡ¢Ñ¹Á¦ºÍ¿ÕËÙÏÂÒ»²½ÆøÏàºÏ³É¶þ¼×ÃÑ¡£COµ¥³Ìת»¯ÂÊ´ïµ½60%¡«83%£¬Ñ¡ÔñÐÔ´ï95%¡£¸Ã¼¼ÊõÏÖËÈÔÚºþ±±ÌïÁ¦¹«Ë¾½¨³ÉÁËÄê²ú1500¶Ö¶þ¼×ÃѵĹ¤Òµ»¯×°Ö᣸Ã×°ÖüȿÉÉú²ú´¼ÃÑȼÁÏ£¬ÓÖ¿ÉÉú²ú99.9%ÒÔÉϵĸߴ¿¶þ¼×ÃÑ£¬COת»¯ÂÊ70%-80%¡£ÕâÊǹúÄÚµÚÒ»Ì×Ö±½ÓÓÉºÏ³ÉÆøÒ»²½·¨Éú²ú¸ß´¿¶þ¼×ÃѵĹ¤Òµ»¯Éú²ú×°Öá£

ÓɹúÄÚ¿ª·¢µÄºÏ³ÉÆøÒ»²½ÆøÏà·¨ÖÆ¶þ¼×ÃѼ¼Êõ»ù±¾³ÉÊ죬²¢Òѽ¨³Éǧ¶Ö¼¶×°Öᣵ«¶ÔÓÚ½¨Éè´óÐͶþ¼×ÃÑ×°Ö㬹úÄÚ¼¼ÊõÉÐÐèʵ¼ùÑéÖ¤¡£

¢ç¶þ¼×ÃÑ·ÖÀë¹ý³ÌÉè¼Æ

¶þ¼×ÃÑ·ÖÀ뾫Áó×°ÖÃͼ£¨Í¼1¡ª1£©

·´Ó¦ºóµÄÆøÌå6ÔÚζÈΪ200¡æ¡«300¡æ £¬Ñ¹Á¦Îª1.5-1.6MPa£¬¾­ÀäÄýÆ÷1ÀäÄý£¬ÀäÄýζÈΪ40¡æ,´ó²¿·Ö¶þ¼×ÃÑÕôÆûÔڴ˱»ÀäÄý£¬¼×´¼ÕôÆûÒ²±»ÀäÄý¡£º¬Óв»ÄýÆøÌåH2¡¢CO¡¢CO2ºÍÉÙÁ¿¶èÐÔÆøÌåºÍCH4¼°Î´ÀäÄýÆøÌåµÄ¶þ¼×ÃÑÆøÌåµÄδÀäÄýÆøÌå 16 ¾­¼õѹµ½

10

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

0.6-4.8MPa£¬½øÈëÎüÊÕËþ¶þϲ¿£¬ÔÚ2.0MPa£¬ÔÚ20¡æ-35¡æÏÂÓÃÈíË®ÎüÊÕ£¬ÀäÄýÆ÷Ò»µÄµ×Á÷²úÎï´Ö¶þ¼×ÃÑÈÜÒº7ºÍÎüÊÕËþ2 µÄµ×Á÷²úÎïÃÑË®ÈÜÒº8½øÈëÉÁÕô¹Þ3£¬ÉÁÕô¹ÞµÄζÈΪ40-100¡æ¡£ÉÁÕôºóµÄÆøÌå9ËÍÈëÎüÊÕËþ2µ×²¿£»ÉÁÕô¹Þ3µ×Á÷²úÎï´¼ÃÑÈÜÒº10£¬½øÈë¶þ¼×ÃѾ«ÁóËþ4£¬Ëþ¶¥²úÎïΪ¾«¶þ¼×ÃÑ12£»µ×Á÷²úÎïΪ´¼ÃÑÈÜÒº11¡£ÃÑË®ÈÜÒº8½øÈëÉÁÕô¹Þ3µÄѹÁ¦Îª0.1-0.9MPa¡£ÉÁÕô¹Þ3µ×Á÷²úÎï´¿ÃÑÈÜÒº10½øÈë¶þ¼×ÃѾ«ÁóËþ4µÄζÈΪ80-150¡æ¡£¶þ¼×ÃѾ«ÁóËþ4µÄѹÁ¦Îª0.15¡ª2.2MPa£¬Ëþ¶¥Î¶ÈΪ20¡ª90¡æ,Ëþ¸ªÎ¶ÈΪ100¡ª200¡æ¡£¶þ¼×ÃѾ«ÁóËþ4µÄµ×Á÷²úÎï´Ö¼×´¼ÈÜÒº11½øÈë¼×´¼»ØÊÕËþ5£¬Æäµ×Á÷²úÎïΪÈíË®13£¬Ëþ²àÏß ²úÎïΪ¾«¼×´¼14¡£¸ß¼¶´¼Å¨¼¯ÓÚ¾«ÁóËþ¶¥²¿Ëþ°åÉϲàÏ߲ɳö¡£¼×´¼»ØÊÕËþµÄѹÁ¦Îª0.1¡ª0.8MPa£¬Ëþ¸ªÎ¶ÈΪ80¡ª150¡æ¡£Ëþ¶¥Î¶ÈΪ40¡ª90¡æ,¡£ÎüÊÕËþÎ²Æø15È¥±äѹÎü¸½»òĤ·ÖÀëÌáÈ¡ÓÐÓóɷÖCO¡¢H2ºó£¬·µ»Ø¶þ¼×ÃѺϳɵ¥Ôª×öºÏ³ÉÔ­ÁÏ¡£

¶þ¼×ÃÑÉú²ú¹ý³Ìϵͳѭ»·½á¹¹Í¼£¨Í¼1¡ª2£©

¶þ¼×ÃÑ·ÖÀ빤ÒÕËþÉè¼Æ£¨Í¼1¡ª3£©

11

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

2¾«ÁóËþ¹¤ÒÕÉè¼Æ

2.1¾«ÁóËþÎïÁϺâËã 2.1.1 »ù´¡Êý¾Ý

£¨Ò»£©Éú²úÄÜÁ¦£º10Íò¶Ö/Ä꣬һÄê°´330Ìì¼ÆË㣬¼´7920Сʱ¡£

£¨¶þ£©²úÆ·¶þ¼×ÃѵĴ¿¶È£º¶þ¼×ÃÑ¡Ý99%¡£

£¨Èý£©¼ÆËã»ù×¼£¨kg/h£©P=108¡Â7920=1.26262¡Á103£¨kg/h£©=274.0669 (mol/h)

2.1.2ÎïÁϺâËã

¢åÎïÁϺâËã×éÖ¯¼òͼ

ÃÑË® DME:0.0309 CH3OH:0.0043 H2O:0.9618 Ëþ¶¥ Ëþµ× DME 8.14¡Á10-5 DME 1000.999 806040200µÚÒ»¼¾¶ÈµÚÈý¼¾¶ÈCH3OH 0.001 ¶«²¿Î÷²¿±±²¿CH3OH 0.9921 H2O 0.9921 12

1008060¶«²¿[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

¢æ ÖÊÁ¿·ÖÊýת»»ÎªÄ¦¶û·ÖÊý

MDME=46.07g/mol MH20 =18.02 g/mol MCH3OH=32.04 g/mol

¸ù¾Ý ai/Mi¡Â¡Æai/MËã³ö£¬ÆäÖÐai¡ªÖÊÁ¿·ÖÊý£»Mi¡ªÄ¦¶ûÖÊÁ¿

¢Å ½øÁÏ×é·Ö

¢Æ Ëþ¶¥×é³É

¢Ç Ëþ¸ª×é³É

¢çÇåÎú·Ö¸î

ÒÔDMEΪÇá¹Ø¼ü×é·Ö£¬CH3OHÎªÖØ¹Ø¼ü×é·Ö£¬H2OΪ·Ç¹Ø¼ü×é·Ö

¢Ù ÎïÁϺâËã

13

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

XW.DME=3.195¡Á10-5 X D.CH3OH=0.001400 D=274.07/0.9986=274.451kmol/h

ÇåÎú·Ö¸î·¨Éè¼Æ¹ý³Ì£¨±í2-4£©

ÁªÁ¢ 0.0123F¡ª3.159¡Á10W£«0.001400D£«0=D

F = D + W

ÒÔÏÂΪ²¿·Öµü´úԭʼÊý¾Ý(µ¥Î»Îªmol/h)

F½øÁÏ 22250 22255 22260 22265 22270 22275 22280 22285 22290 22295 22300 22305 22310 22315 22320 22325 22330 22335 22340 22345 22350 22355 22360 22365 22370 22375

-5

WËþ¸ª 21975.54887 21980.54887 21985.54887 21990.54887 21995.54887 22000.54887 22005.54887 22010.54887 22015.54887 22020.54887 22025.54887 22030.54887 22035.54887 22040.54887 22045.54887 22050.54887 22055.54887 22060.54887 22065.54887 22070.54887 22075.54887 22080.54887 22085.54887 22090.54887 22095.54887 22100.54887 DËþ¶¥ 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113

14

×ó±ß 273.365024 273.426366 273.4877081 273.5490501 273.6103922 273.6717342 273.7330763 273.7944183 273.8557604 273.9171024 273.9784445 274.0397865 274.1011286 274.1624706 274.2238127 274.2851547 274.3464968 274.4078388 274.4691809 274.5305229 274.591865 274.653207 274.7145491 274.7758911 274.8372332 274.8985752 ÓÒ±ßD 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113 274.45113

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

22380 22385 22390 22395 22105.54887 22110.54887 22115.54887 22120.54887

274.45113 274.45113 274.45113 274.45113

274.9599173 275.0212593 275.0826014 275.1439434

274.45113 274.45113 274.45113 274.45113

Óɴ˿ɵÃF=22340kmol/h w=22065kmol/h D=274.45kmol/h

¢è ¾«Á󹤶ι¤ÐòÎïÁϺâËã±í

±í2-5¾«Áó¹¤ÐòÎïÁϺâËã±í

ÖÊÁ¿Á÷ÂÊÖÊÁ¿·ÖÊý Ħ¶ûÁ÷ÂÊ£¨kg/h£© £¨kmol/h£© 12659.21 176.7961 39660.88 12631.32 8.79341 88.4407 3119.904 395831.9 0.03090 0.004300 0.9648 0.999 0.001 8.14¡Á10-5 0.007819 0.9921 274.782 55.1798 22009.37 274.1767 0.27445 1.9197 97.37527 21966.25 ÁÏÏò ½ø ÁÏ ³ö ÁÏ Ëþ ¶¥ Ëþ ¸ª ×é·Ö DME CH3OH H2O DME CH3OH DME CH3OH H2O Ħ¶û·ÖÊý 0.01230 0.002470 0.9852 0.9986 0.0014 3.195¡Á10-5 0.004413 0.9955

15

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

2.2¾«Á󹤶ι¤ÒÕ¼ÆËã 2.2.1ÎïÁϺâË㣨¼û2.1.2£© 2.2.2²Ù×÷Ìõ¼þµÄÈ·¶¨

£¨Ò»£©½øÁÏζȵļÆË㣨Åݵ㣩¡ª±¥ºÍÒºÌå½øÁÏ

£¨1£©ÒÑÖªÌåϵ×ÜѹǿP×Ü=200kpa, ¼´P×Ü=1520mmHgÎïÁϱ¥ºÍÒºÌå½øÁÏ£¬¹Ê½øÁϵÄÅݵãζÈΪ½øÁÏζȡ£

£¨2£©°²ÍÐÍò¹«Ê½

Ln Pis = A ¨C B/(T+C) (Pis :mmHg, T: K) ²é¡¶Ê¯ÓÍ»¯¹¤»ù´¡Êý¾ÝÊֲᡷ

±í2-6°²ÍÐÍò¹«Ê½Êý¾Ý±í

£¨3£©²ÉÓÃÊԲ¼ÆËã

ѹÁ¦²»Ì«¸ßʱ°´ÍêÈ«ÀíÏëÏ¢¼ÆË㣬Ki=ln Pis/p

T ¸ø¶¨P Y É趨T Ki=ln Pis/p ¡ÆKiXi - 1¡Ü¦Å ½áÊø

µ÷ÕûT N yi

ͼ2-2ÊԲ½á¹¹Í¼

16

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

ÊÔ²î¹ý³Ì¼û±í2-7

±í2-7½øÁÏζÈÊÔ²î¹ý³Ì

½á¹ûÔÚ392.70K£¬¼´119.55¡æÊ±£¬¡ÆKiXi¡Ö1,¹Ê½øÁÏζÈΪ392.70K

(¶þ) Ëþ¶¥Â¶µãζȼÆËã

²Ù×÷ѹÁ¦£ºP×Ü==1520mmHg

T ¸ø¶¨P Y É趨T Ki=ln Pis/p ¡Æyi/Ki¡Ü¦Å ½áÊø µ÷ÕûT N Xi

ͼ2-3ÊԲ½á¹¹Í¼

ÊÔ²î¹ý³Ì¼û2-8

±í2-8ÊÔ²î¹ý³Ì

½á¹û£º¼´ÔÚ332.25K,¼´59.10¡æÊ±ÊÕÁ²£¬¹ÊËþ¶¥Î¶ÈΪ332.25K (Èý) Ëþ¸ªÅݵãζȼÆËã ²Ù×÷ѹÁ¦£ºP×Ü=1520mmHg

T ¸ø¶¨P Y É趨T Ki=ln Pis/p ¡ÆKiXi - 1¡Ü¦Å ½áÊø

µ÷ÕûT N yi

ͼ2-4ÊԲ½á¹¹Í¼

17

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

½á¹ûÔÚ393.50K¼´120.35¡æÊ±£¬¡ÆKiXi¡Ö1,¹Ê½øÁÏζÈΪ393.50K

2.3¾«ÁóËþÉ豸¼ÆËã 2.3.1»ù´¡Êý¾Ý

£¨Ò»£© Ëþѹ£º1520mmHg ½øÁÏζȣºTF=392.70K

ËþΠËþ¶¥Î¶ȣºTD =332.25K

Ëþ¸ªÎ¶ȣºTW =393.50K

£¨¶þ£©ÃܶÈ

¾­Äڲ巨ËãµÃ£º

18

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

ÒÑÖª¸÷×é·ÖÔÚÒºÏà¡¢ÆøÏàËùÕ¼µÄ±ÈÀý£¬Èç±í2-12Ëùʾ

£¨1£© Ëþ¶¥ÃܶȵļÆËã

¢Ù ÒºÏàÆ½¾ùÃÜ:

¢Ú ÆøÏàÆ½¾ùÃܶȣº

£¨2£©½øÁϰåÃܶȵļÆËã ¢ÙÒºÏàÆ½¾ùÃÜ:

¢ÚÆøÏàÆ½¾ùÃܶÈ

19

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

£¨2£© Ëþ¸ªÃܶȵļÆËã

¢Ù ÒºÏàÆ½¾ùÃܶȣº

¢Ú ÆøÏàÆ½¾ùÃܶȣº

¢Û ¾«Áó¶ÎºÍÌáÁó¶ÎµÄÃܶȼÆËã

¾«Áó¶Î

ÌáÁó¶Î

£¨Èý£©ð¤¶ÈµÄ¼ÆËã

20

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

¾­¼ÆËãµÃ

21

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

2.3.2Ëþ°åÊýµÄÈ·¶¨

£¨Ò»£©×îС»ØÁ÷±ÈRminµÄÈ·¶¨ ¢ÙÏà¶Ô»Ó·¢¶È

±¾Éè¼ÆÒÔDMEΪÇá¹Ø¼ü×é·ÖA; CH3OHÎªÖØ¹Ø¼ü×é·ÖB£»H20Ϊ·Ç¹Ø¼ü×é·ÖC;ÒÔÖØ¹Ø¼ü×é·ÖΪ»ù×¼Î¼´¦Á

BB = 1¡£

¢Ú×îС»ØÁ÷±ÈRmin

±¾Éè¼ÆÎªÅÝµã½øÁÏ£¬¼´±¥ºÍÒºÌå½øÁÏ£¬q=1 ¶÷ÌØÎéµÂ¹«Ê½£º

£¨¶þ£©Êµ¼Ê»ØÁ÷±È

ȡʵ¼Ê»ØÁ÷±ÈΪ×îС»ØÁ÷±ÈµÄ1.15±¶£¬ ÔòR=1.15Rmin=1.15¡Á2.427=2.791

22

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

£¨Èý£©×îСÀíÂÛ°åÊýµÄÈ·¶¨

¹Ê×îСÀíÂÛËþÊýNmin =3.853 (²»°üÀ¨ÔÙ·ÐÆ÷) £¨Ò»£© È«ËþÀíÂÛ°åÊýµÄÈ·¶¨

ÓÉ¡¶»¯¹¤Ô­Àí¡·Ï²ἪÀûÀ¼Í¼²éµÃ

Nmin=3.853´úÈË£¬ÇóµÃN=10.7£¨²»°üÀ¨ÔØ·ÐÆ÷£©

£¨¶þ£© ¾«Áó¶ÎºÍÌáÁó¶ÎÀíÂÛ°åÊýµÄÈ·¶¨

ƽ¾ùÏà¶Ô»Ó·¢¶È£º

£¨Èý£© ʵ¼Ê°åÊýµÄÈ·¶¨

¢Ù °åЧÂÊ

23

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

¢Ú ËþÄÚʵ¼Ê°åÊý

ȡʵ¼Ê°å²ãÊýΪ27¿é£¨²»°üÀ¨ÔÙ·ÐÆ÷£©

£¨ËÄ£© ¾«Áó¶ÎºÍÌáÁó¶Îʵ¼Ê°åÊý

ȡʵ¼Ê¾«Áó¶ÎËþ°åÊýΪ12¿é£¬ÌáÁó¶Îʵ¼Ê°åÊýΪ15¿é£¬½øÁϰåµÄλÖÃΪÓÉϵ½ÉÏÊýµÄµÚÊ®Áù¿é°å

2.3.3¾«ÁóËþÖ÷Òª³ß´ç¼ÆËã

£¨Ò»£©Á÷Á¿¼ÆËã

£¨1£© ½øÁÏ£º

DME: FxDME= 12659.21 (kg/h) =3.51645(kg/s) CH3OH: FxCH3O=1767.961(kg/h)=0.4911(kg/s) H2O: FxH20= =39660.88 (kg/h)=110.1691(kg/h)

(2) ¾«Áó¶Î£º ÆøÏàÁ÷Á¿£º

V=L+D=(R+1)D=3.791¡Á274.45=1040.44(kmol/h) =0.289011(kmol/s)=3352.98(kg/h)=9.311938(kg/s) 0.2890¡Á32.67 2.259 2.259 =4.179£¨m3/s£© Vh=15046.9(m3/h) ÒºÏàÁ÷Á¿£º

L=RD=2.791¡Á274.45113=765.993(kmol/h)=0.21277( kmol/s)

=6.8556(kg/s)=24680.29(kg/h)

LS=(0.21277*32.22)/749.8=0.009143£¨m3/s£©

24

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

Lh=32.9149(m3/h)

(3) ÌáÁó¶Î£º ÆøÏàÁ÷Á¿

V¡¯=V=1040.44(kmol/h)=0.289011(kmol/s)=3352.98(kg/h)=9.311938(kg/s) VS¡¯=(0.289011¡Á18.75)/1.148=4.720345£¨m3/s£© Vh¡¯=1.6993¡Á104(m3/h) ÒºÏàÁ÷Á¿

L¡¯=L+F=765.993+22340=23105.993(kmol/h)=6.418( kmol/s) =4.2145¡Á105(kg/h)=117.07(kg/s) Ls¡¯=(6.418¡Á18.24)¡Â922.8=0.126857(m3/s) Lh¡¯=456.68(m3/h) (¶þ)Ëþ¾¶µÄ¼ÆËã

£¨2£© ¾«Áó¶Î¼ÆË㣺

???L???????V????0.5?Ls ??V?s474.98??0.0091??3?????4.1932.259????0.5?0.0397 26 ³õÑ¡Ëþ°å¼ä¾àHT?350mm¼°°åÉÏÒº²ã¸ß¶ÈhL?70mm£¬Ôò£º

HT?hL?0.35?0.07?0.28m

25

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

¸ù¾ÝÒÔÉÏÊý¾Ý£¬²éÊ·ÃÜ˹¹ØÁªÍ¼C20?0.054¡£ÓÉÓÚÎïϵ±íÃæÕÅÁ¦Îª30.62dyn/cm,²»½Ó

???½üC20,ÐèҪУÕý£ºC?C20??20??0.2?30.62??0.054??20??0.2?0.06400

umax?C??L??V?/?V?0.064?847.1?2.894?/2.259?1.164(m/s)

È¡°²È«ÏµÊýΪ0.7£¬Ôòu?0.7umax?0.815m/s Ëþ¾¶£ºD?4Vs/?u?4?1.254/3.14?0.8150?1.397m

°´±ê×¼Ëþ¾¶Ô²ÕûΪD=1.4m£¬ÔòËþÃæ»ý£ºA=1.539(m)

¿ÕËþÆøËÙ£ºu=0.8146£¨m/s£© (3)ÌáÁó¶Î¼ÆË㣺

?Ls'???L'???V'?????'???s??V?0.5?0.12685??922.8??????4.72031.148????0.5?0.7619È¡Ëþ°å¼ä¾àHT'?400mm¼°°åÉÏÒº²ã

¸ß¶ÈhL'?0.09m£¬Ôò£ºHT'?hL'?0.4?0.09?0.31m

¸ù¾ÝÒÔÉÏÊý¾Ý£¬²éÊ·ÃÜ˹¹ØÁªÍ¼C20'?0.02599¡£ÓÉÓÚÎïϵ±íÃæÕÅÁ¦Îª54.30dyn/cm,

???²»½Ó½üC20¡¯,ÐèҪУÕý£ºC'?C20'??20??0.2?54.30??0.02599??20??0.2?0.0317

umax'?C'??L'??V'?/?V'?0.03174?922.8?1.148?/1.148?0.899(m/s)

È¡°²È«ÏµÊýΪ0.7£¬Ôòu'?0.7umax'?0.6295m/s Ëþ¾¶£ºD'?4Vs/?u?4?1.416/3.14?0.6295?1.693m

°´±ê×¼Ëþ¾¶Ô²ÕûΪD=1.8m£¬ÔòËþÃæ»ý£ºA=2.545(m)

¿ÕËþÆøËÙ£ºu¡¯=0.5565£¨m/s£©

2.3.4Ëþ°å½á¹¹Éè¼Æ

£¨Ò»£©¾«Áó¶Î

°å¼ä¾à HT=0.35m,È¡°åÉÏÒº²ã¸ß¶ÈhL=0.07m Ëþ¾¶D=1.4m

¸ù¾ÝËþ¾¶ºÍÒºÌåµÄÁ÷Á¿£¬Ñ¡Óù­ÐνµÒº¹Ü£¬²»Éè½ø¿ÚÑߣ¬Ëþ°å²ÉÓõ¥ÒçÁ÷ºÍ·Ö¿éʽ×é×°¡£

(1) ÒçÁ÷×°Öà ¢Ù Ñß³¤lW

È¡Ñß³¤lW=0.65D£¬¼´lW=0.65¡Á1.4=0.91£¨m£© ¢Ú ÑßÉÏÒº²ã¸ß¶ÈhOW

26

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

how?0.00284?1.02?7.680/0.91?¢Û ³ö¿ÚÑ߸ߣºhw?hL?how

2/3?0.011990782m?0.006m

·ûºÏÒªÇó¡£Ò»°ãÒªÇóÑßÉÏÒº²ã¸ß¶È²»Ð¡ÓÚ6mm£¬ÒÔÃâÒºÌåÔÚÑßÉÏ·Ö²½¾ùÔÈ¡£

hw?hL?how?0.07?0.01199?0.05801m

¢Ü ½µÒº¹ÜµÄµ×϶¸ß¶Èho

ÒºÌåͨ¹ý½µÒº¹Üµ×϶µÄÁ÷ËÙÒ»°ãΪ0.07~0.25m/s£¬È¡ÒºÌåͨ¹ý½µÒº¹Üµ×϶µÄÁ÷ËÙ

??0.08m/s£¬ÔòÓУº uoho?Ls0.009143 ??0..12559m£¨ho²»ÒËСÓÚ0.02~0.025m£¬±¾½á¹ûÂú×ãÒªÇó£©

?0.91?0.08lwuo

¢Ý½µÒº¹ÜµÄ¿í¶ÈWdºÍ½µÒº¹ÜµÄÃæ»ýAfÓÉlw/D?0.65£¬²é»¯Ô­ÏÂP147ͼ11-16µÃWd/D?0.126,Af/AT?0.07£¬¼´£º

Wd?0.1764m£¬AT?0.785D2?1.5386m2£¬Af?0.107702m2¡£

¢ÞÒºÌåÔÚ½µÒº¹ÜÄÚµÄÍ£Áôʱ¼ä

??AfHT/Ls?0.1077?0.35/0.009143?4.12282s?5s£¨²»·ûºÏÒªÇó£©

¹ÊÖØÐÂÐÞÕý²ÎÊýѡȡ£ºHT=500mm ´Ëʱ

£© ??AfHT/Ls?0.1077?0.5/0.009143?5.889752s?5s £¨·ûºÏÒªÇó¡£

£¨3£© Ëþ°å²¼Öü°¸¡·§ÊýÄ¿ÅÅÁУº

27

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

¸¡·§ÅÅÁз½Ê½²ÉÓõÈÑüÈý½ÇÐβæÅÅ¡£

2.4¸¡·§ËþÌáÁï¶ÎÓ뾫Áó¶ÎÉè¼Æ²ÎÊý»ã×Ü

ÌáÁô¶ÎÓ뾫Áó¶ÎµÄËã·¨Ò»Ö£¬½á¹û¼ûºó×Ü±í¡£

±í2-22 ¸¡·§Ëþ¹¤ÒÕÉè¼Æ¼ÆËã×ܱí Ëþ¾¶D,m Ëþ¸ßH,m Ëþ°åÐÍʽ Ëþ°åÊý£¨²ã£© ¿ÕËþÆøÊýu,m/s Ñß³¤l,m Ñ߸ßh,m ½µÒº¹Üµ×϶¸ß¶Èho,m ¸¡·§ÊýN£¬¸ö ·§¿×ÆøËÙu,m/s ·§¿×¶¯ÄÜÒòÊýFu Áٽ緧¿×ÆøËÙm/s ¿×Ðľà t,m Åżä¾à t¡¯m µ¥°åѹ½µ Pa ÒºÌåÔÚ½µÒº¹ÜÄÚÇåÒº²ã¸ß¶È H,m ÒºÌåÔÚ½µÒº¹ÜÄÚÍ£Áôʱ¼ä¦È,s ·ºµãÂÊ£¥ 33ÊýÖµ¼°ËµÃ÷ ¾«Áó¶Î ÌáÁó¶Î ±¸ ×¢ ÆøÏฺºÉÉÏÏÞ£¨VS£©max,m/s ÆøÏฺºÉÏÂÏÞ£¨VS£©min,m/s

28

[Äê²úÊ®Íò¶Ö¶þ¼×ÃÑ×°Ö÷ÖÀ뾫Á󹤶εŤÒÕÉè¼Æ]

Annual output of 10,000 tons of dimethyl ether distillation

Section in the design of sepration device

INTRODUCTION

Motor Vehicle population is increasing in China,and the country is faced with a serious energy supply problem. China¡¯s smaller reserves of petroleum and risingdemand for petroleum products result in a net import postion which is not likely to be reversed. Therefore,strong effeorts should be made to find commercially viable alternatives to imported oil and oil products for automobiles to satisfy the short-and medium-term needs of the country. DME is one of the promising fuel substitutes for petroleum diesel fuel which can be used by compression ignition engines because it is a clean fuel with good self-ignition characteristics and almost smoke-free combustion. Numerous investigation of DME-fulled engines have indicated that DME offers an excellent promise as an alternative fuel for compression-ignition operation in the automotive sector with its ultra-low emissions.

The use of dimethyl ether(DME)as an alternative fuel appears to be a promising approach for simultaneously minimizing NOx and soot emission from conventional diesel engines. The low self-ignition temperature of 508K and the high oxygen content

Of 34.8 percent(mass fraction) are two major factors characterizing low soot and unburned total hydrocarbon(THC)emission

Preparation of dimethyl ether mainly methanol dchydration and One-step synethesis. With the tradional methanol synethesis compared to synethesis of dimethyl ether,one-step synethesis of dimethyl ether process more rational economy, more competive in the market and it is moving towards industrialiazation. Curently , synethesis gas to dimethyl ether is the latest technology preparation of dimethyl ether. Compared with methanol dchydration , system of direct synthesis of DME as the existence of unreacted synthesis gas and carbon dioxide finished.If it want to get high purity dimethyl ether, more complicated separation process. Developed mainly in the separation process such as chemical absorption and distillation unit operation in the process of dimethylethyl ether with higher purity product.This design aimed at separating the distillation process for process design. Separation of DME , methanol and water ternary system. Design of distillation towers used valve. Use the whole top of the tower condenser cooling device used to provide sufficient heat.Obtained by calculating the number of theoretical plate design and calculation of process dimensions derived column diametet, the effective tower, sieve number. Checking through the sieve of fluid mechanics, to prove that the indicator data are in line with standards to ensure the smooth progress of distillation process and to improve efficiency as much as possible.

29