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SQL> SELECT DEPARTMENT_ID AS ²¿ÃźÅ,AVG(SALARY) AS ƽ¾ù¹¤×Ê 2 ,MAX(SALARY) AS ×î¸ß¹¤×Ê,MIN(SALARY) AS ×îµÍ¹¤×Ê 3 ,COUNT(*) AS ÈËÊý 4 FROM EMPLOYEES
5 GROUP BY DEPARTMENT_ID
6 ORDER BY DEPARTMENT_ID ASC;
²¿ÃźŠƽ¾ù¹¤×Ê ×î¸ß¹¤×Ê ×îµÍ¹¤×Ê ÈËÊý ------ ---------- ---------- ---------- ----------
10 4400 4400 4400 1
20 9500 13000 6000 2
30 4150 11000 2500 6
40 6500 6500 6500 1
50 3475.55555 8200 2100 45
60 5760 9000 4200 5
70 10000 10000 10000 1
80 8973.85294 14000 6100 34
90 21333.3333 24000 20000 3
100 8600 12000 6900 6
110 10150 12000 830
0 2
7000 7000 7000 1
12 rows selected
/*--------2¡¢¸÷¸ö²¿ÃÅÖй¤×Ê´óÓÚ5000µÄÔ±¹¤ÈËÊý¡£---------*/ SQL> SELECT DEPARTMENT_ID,COUNT(*) FROM EMPLOYEES 2 WHERE SALARY > 5000
3 GROUP BY DEPARTMENT_ID;
DEPARTMENT_ID COUNT(*) ------------- ---------- 20 2 30 1 40 1 50 5 60 2 70 1 80 34 90 3 100 6 110 2 1
11 rows selected
/*--------3¡¢¸÷¸ö²¿ÃÅÆ½¾ù¹¤×ʺÍÈËÊý£¬°´ÕÕ²¿ÃÅÃû×ÖÉýÐòÅÅÁС£---------*/
SQL> SELECT DPTNAME,AVG(SALARY),COUNT(*) FROM 2 (SELECT
3 (SELECT DEPT.DEPARTMENT_NAME FROM DEPARTMENTS DEPT
4 WHERE DEPT.DEPARTMENT_ID = EMP.DEPARTMENT_ID) DPTNAME, 5 EMP.SALARY 6 FROM EMPLOYEES EMP) 7 GROUP BY DPTNAME 8 ORDER BY DPTNAME;
DPTNAME AVG(SALARY) COUNT(*) ------------------------------ ----------- ---------- Accounting 10150 2 Administration 4400 1 Executive 21333.33333 3
Finance 8600 6 Human Resources 6500 1 IT 5760 5 Marketing 9500 2 Public Relations 10000 1 Purchasing 4150 6 Sales 8973.852941 34 Shipping 3475.555555 45 7000 1 12 rows selected
--»òÕß--
SQL> SELECT DEPT.DEPARTMENT_NAME,AVG(EMP.SALARY),COUNT(*) 2 FROM EMPLOYEES EMP,DEPARTMENTS DEPT
3 WHERE EMP.DEPARTMENT_ID = DEPT.DEPARTMENT_ID 4 GROUP BY DEPT.DEPARTMENT_NAME 5 ORDER BY DEPT.DEPARTMENT_NAME;
DEPARTMENT_NAME AVG(EMP.SALARY) COUNT(*) ------------------------------ --------------- ---------- Accounting 10150 2 Administration 4400 1 Executive 21333.333333333 3 Finance 8600 6 Human Resources 6500 1 IT 5760 5 Marketing 9500 2 Public Relations 10000 1 Purchasing 4150 6 Sales 8973.8529411764 34 Shipping 3475.5555555555 45
11 rows selected
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SQL> SELECT EMP1.DEPARTMENT_ID,EMP1.SALARY,COUNT(*) CNT 2 FROM EMPLOYEES EMP1,EMPLOYEES EMP2
3 WHERE EMP1.DEPARTMENT_ID = EMP2.DEPARTMENT_ID AND 4 EMP1.SALARY = EMP2.SALARY
5 AND EMP1.EMPLOYEE_ID <> EMP2.EMPLOYEE_ID
6 GROUP BY EMP1.DEPARTMENT_ID,EMP1.SALARY;
DEPARTMENT_ID SALARY CNT ------------- ---------- ---------- 50 2200.00 2 50 2400.00 2 50 2500.00 20 50 2600.00 6 50 2700.00 2 50 2800.00 6 50 2900.00 2 50 3000.00 2 50 3100.00 6 50 3200.00 12 50 3300.00 2 50 3600.00 2 60 4800.00 2 80 7000.00 2 80 7500.00 2 80 8000.00 6 80 9000.00 2 80 9500.00 6 80 10000.00 6 80 10500.00 2 80 11000.00 2 90 20000.00 2
22 rows selected
/*--------5¡¢Áгöͬ²¿ÃÅÖй¤×ʸßÓÚ1000 µÄÔ±¹¤ÊýÁ¿³¬¹ý2 È˵IJ¿ÃÅ£¬ ÏÔʾ²¿ÃÅÃû×Ö¡¢µØÇøÃû³Æ¡£---------*/
SQL> SELECT D.DEPARTMENT_NAME,L.CITY,COUNT(*) 2 FROM EMPLOYEES E,DEPARTMENTS D,LOCATIONS L 3 WHERE E.DEPARTMENT_ID = D.DEPARTMENT_ID AND 4 D.LOCATION_ID = L.LOCATION_ID AND 5 E.SALARY > 1000
6 GROUP BY D.DEPARTMENT_NAME,L.CITY 7 HAVING COUNT(*) > 2;
DEPARTMENT_NAME CITY COUNT(*)
------------------------------ ------------------------------ ----------