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A. 3£¬2 ; B.3£¬1 ; C. 2£¬0£» D. 2£¬1

3.ÔÚ2ÌâÖÐÒÑ´ïÆ½ºâµÄϵͳÖмÓÈëCO2 (g)ʱ£¬ÏµÍ³ÖØÐÂ´ïÆ½ºâºó£¬ÔòϵͳµÄ×é·ÖÊýC=( ),F=( ).

A. 3£¬2 ; B.3£¬1 ; C. 2£¬0£» D. 2£¬1 4.A(l)ºÍB(l)¿ÉÐγÉÀíÏëҺ̬»ìºÏÎÈôÔÚζÈTÏ£¬´¿A(l)µÄ±¥ºÍÕôÆûѹΪp?A´óÓÚ

?´¿B(l)µÄ±¥ºÍÕôÆûѹΪpB¡£ÔòÔÚ¶þ×é·ÖµÄÕôÆøÑ¹-×é³ÉͼÉÏµÄÆø¡¢ÒºÁ½ÏàÆ½ºâÇø£¬³Ê

ƽºâµÄÆø¡¢ÒºÁ½ÏàµÄ×é³ÉÓУ¨ £©¡£

A. yB>xB ; B. yB

5.ÈôA(l)ºÍB(l)¿ÉÐγÉÀíÏëҺ̬»ìºÏÎÔÚζÈTÏ£¬´¿A(l)µÄ±¥ºÍÕôÆûѹΪp?A<´¿

?B(l)µÄ±¥ºÍÕôÆûѹΪpB¡£Ôòµ±»ìºÏÎïµÄ×é³ÉΪ0

?¿´³öÕôÆø×ÜѹpÓëp?¡¢¡£ pABµÄÏà¶Ô´óСΪ£¨ £©??? A. P>pB ; B. P

6.ÔÚζÈTÏ£¬CaCO3 (s),CaO(s)¼°CO2 (g)µÄƽºâѹÁ¦Îªp£¬ÒÑÖªËüÃÇÖ®¼ä´æÔÚ£º CaCO3 (s) = CaO(s) + CO2 (g)·´Ó¦£¬ÈôÍù¸Ãƽºâϵͳ¼ÓÈëCO2 (g)£¬µ±ÖØÐ´ﵽƽºâʱ£¬ÏµÍ³µÄѹÁ¦£¨ £©¡£

A. ±ä´ó ; B. ±äС ; C. ²»±ä£» D. ¿ÉÄܱä´óÒ²¿ÉÄܱäС 7.ÒÑÖªCuSO4 (s)ÓëH2O(g)¿ÉÐγÉÏÂÁÐÈýÖÖ»¯ºÏÎ CuSO4 (s) + H2O(g) = CuSO4?H2O(s)

CuSO4?H2O(s) + 2H20(g) = CuSO4?3H2O(s) CuSO4?3H2O(s) + 2H2O = CuSO4?5H2O(s)

ÔÚ101.325kPaÏ£¬ÓëH2O(g)ƽºâ¹²´æµÄÑÎ×î¶àÓм¸ÖÖ¡£ A. 1 ; B. 2 ; C. 3£» D. 4

8.ÔÚA(µÍ·Ðµã)ÓëB(¸ß·Ðµã) Á½ÖÖ´¿ÒºÌå×é³ÉҺ̬ÍêÈ«»¥ÈܵįøÒºÆ½ºâϵͳ¡£ÔÚÒ»¶¨µÄζÈÏ£¬½«B(l) ¼ÓÈëÆ½ºâϵͳÖÐʱ£¬²âµÃϵͳµÄѹÁ¦Ôö´ó£¬ËµÃ÷´Ëϵͳ£¨ £©¡£ A. Ò»¶¨¾ßÓÐ×î´óÕýÆ«²î ; B. Ò»¶¨¾ßÓÐ×î´ó¸ºÆ«²î ; C. ¿ÉÄܾßÓÐ×î´óÕýÆ«²îÒ²¿ÉÄܾßÓÐ×î´ó¸ºÆ«²î; D. Êý¾Ý²»¹»£¬ÎÞ·¨È·¶¨

9.ÔÚ318KÏ£¬±ûͪ(A)ºÍÂÈ·Â(B) ×é³ÉҺ̬»ìºÏÎïµÄÆøÒºÆ½ºâϵͳ£¬ÊµÑé²âµÃxB=0.3Ê±ÆøÏàÖбûͪµÄƽºâÕôÆø·ÖѹpA=26.77kPa,ÒÑ֪ͬζÈϱûͪµÄ±¥ºÍÕôÆøÑ¹¡£ p?A=43.063kPa,Ôò´ËҺ̬»ìºÏÎïΪ£¨ £©

A.ÀíÏëҺ̬»ìºÏÎï ; B.¶Ô±ûͪ²úÉúÕýÆ«²î ; C.¶Ô±ûͪ²úÉú¸ºÆ«²î; D.ÎÞ·¨È·¶¨

10.ÔÚζÈTÏ£¬A(l)ÓëB(l) ÐγÉÀíÏëҺ̬»ìºÏÎïµÄÆøÒºÆ½ºâϵͳ£¬ÒÑÖªÔÚ¸ÃζÈÏ£¬

?A(l)ÓëB(l) µÄ±¥ºÍÕôÆøÑ¹Ö®±Èp?/pAB?5ʱ£¬Èô¸ÃÆøÒºÆ½ºâϵͳµÄÆøÏàÖÐBÖ®×é³É

yB=0.5,ÔòƽºâÒºÏàÖеÄxB=£¨ £©¡£

A. 0.152 ; B. 0.167 ; C. 0.174; D.0.185

11.×é·ÖA(s)Óë×é·ÖB(s£©×é³ÉµÄÄý¾ÛϵͳÏàͼÖУ¬ÈôÒÑÖªÐγÉÒÔÏÂËÄÖÖ»¯ºÏÎ A2B(Îȶ¨),AB(Îȶ¨),AB2 (²»Îȶ¨),AB3 (Îȶ¨)Ôò¸ÃÏàͼÖÐÓУ¨ £©×îµÍ¹²ÈÛµãºÍ£¨ £©ÌõÈýÏàÏß¡£

A. 3£¬3 ; B. 4£¬4 ; C. 3£¬4 ; D. 4£¬5

12.NH4HS(s)ºÍÈÎÒ»Á¿µÄNH3(g)¼°H2S(g)´ïƽºâʱÓÐ( ).

A. C=2,P=2,F=2 B. C=1,P=2,F=1 C. C=1,P=3,F=2 D. C=1,P=2,F=3 13.¶ÔÓÚºã·Ð»ìºÏÎï,ÏÂÁÐ˵·¨ÖдíÎóµÄÊÇ( )

A.²»¾ßÓÐÈ·¶¨×é³É; B.ƽºâÊ±ÆøÏà×é³ÉÓëÒºÏà×é³ÉÏàͬ

C.Æä·ÐµãËæÍâѹµÄ±ä»¯¶ø±ä»¯; D. Ó뻯ºÏÎïÒ»Ñù¾ßÓÐÈ·¶¨×é³É

14.ÔÚ101.325kPaµÄѹÁ¦ÏÂ,I2ÔÚҺ̬ˮºÍCCl4Öдﵽ·ÖÅ䯽ºâ(ÎÞ¹Ì̬µâ´æÔÚ)Ôò¸ÃϵͳµÄÌõ¼þ×ÔÓɶÈÊýΪ( ).

A. F¡¯=1 B. F¡¯=2 C. F¡¯=0 D. F¡¯=3

15.ÁòËáÓëË®¿ÉÐγÉH2SO4?H2O(s), H2SO4?2H2O(s), H2SO4?4H2O(s)ÈýÖÖ»ìºÏÎï,ÎÊÔÚ101325PaµÄѹÁ¦ÏÂ,ÄÜÓëÁòËáË®ÈÜÒº¼°±ùƽºâ¹²´æµÄÁòËáË®ºÏÎï×î¶à¿ÉÓжàÉÙÖÖ?( )

A.3ÖÖ B.2ÖÖ C.1ÖÖ D.²»¿ÉÄÜÓÐÁòËáË®ºÏÎïÓë֮ƽºâ¹²´æ

16.ijƽºâ´æÔÚC(s),H2O(g),CO(g),CO2(g)ºÍH2(g)ÎåÖÖÎïÖÊ,Ï໥½¨Á¢ÁËÏÂÊöÈý¸öƽºâ: H2O(g) + C(s) = H2(g) + CO(g)

CO2(g) + H2(g) = H2O(g) + CO(g)

CO2(g) + C(s) = 2CO(g) Ôò¸ÃϵͳµÄ¶ÀÁ¢×é·ÖÊýCΪ( ). A.3 B. 2 C. 1 D. 4

17.×é·ÖA(¸ß·Ðµã)Óë×é·ÖB(µÍ·Ðµã)ÐγÉÍêÈ«»¥ÈܵĶþ×é·Öϵͳ,ÔÚÒ»¶¨Î¶ÈÏÂ,Ïò´¿BÖмÓÈëÉÙÁ¿A ,ϵͳÕôÆøÑ¹Ôö´ó,Ôò´ËϵͳΪ( )

A.ÓÐ×î¸ßºã·ÐµãµÄϵͳ B.²»¾ßÓкã·ÐµãµÄϵͳ

C.ÓÐ×îµÍºã·ÐµãµÄϵͳ D.ÎÞ·¨È·¶¨ ¶þ¡¢Ìî¿ÕÌâ

1.ÔÚÕæ¿ÕÈÝÆ÷ÖзÅÈë¹ýÁ¿µÄNH4I(s)ÓëNH4Cl(s),²¢·¢ÉúÒÔÏ·ֽⷴӦ£º NH4I(s) =NH3 (g) + HI(g) NH4Cl(s) =NH3 (g) + HCl(g)

´ïƽºâºó£¬ÏµÍ³µÄ×é·ÖÊýC=( ),ÏàÊýP=( ),×ÔÓɶÈÊýF=( )

2.Na2CO3 (s)ÓëH2O(l)¿ÉÉú³ÉNa2CO3?H2O(s)£¬Na2CO3?7H2O(s), Na2CO3?10H2O(s),Ôò

30¡æÊ±£¬ÓëNa2CO3Ë®ÈÜÒº¡¢±ùƽºâ¹²´æµÄË®ºÏÎï×î¶àÓУ¨ £©ÖÖ¡£ 3.ÔÚ³é¿ÕµÄÈÝÆ÷ÖзÅÈëNH4HCO3 (s),·¢ÉúÈçÏ·´Ó¦£º

NH4HCO3 (s) = NH3 (g) + CO2 (g) + H2O(g)ÇҴﵽƽºâ£¬ÔòÕâ¸öϵͳµÄ×é·ÖÊýC=( ),×ÔÓɶÈÊýF=( ).

4.½«Ò»¶¨Á¿NaCl(s)ÈÜÓÚË®ÖÐÐγɲ»±¥ºÍÈÜÒº£¬¼ÙÉèNaClÍêÈ«µçÀ룬H2O(l)¿É½¨Á¢µçÀëÆ½ºâ£¬Àë×ÓÎÞË®ºÏ·´Ó¦£¬ÔòϵͳµÄC=( );F=( ).

5.×ÔÓɶÈÊýµÄÎÄ×Ö¶¨ÒåΪ( ),ÏàÂɵÄÊýѧ±í´ïʽÊÇ£¨ £©¡£

6.º¬ÓÐKNO3ÓëNaClµÄË®ÈÜÒºÓë´¿Ë®´ïÉøÍ¸Æ½ºâʱ£¬Æ½ºâÌåϵµÄ×ÔÓɶÈÊýΪ£¨ £©¡£

7. NaHCO3 (s)ÔÚÕæ¿ÕÈÝÆ÷Öв¿·Ö·Ö½âΪNa2CO3 (s)¡¢H2O(g)ºÍCO2 (g)´ïƽºâʱ£¬¸ÃÌåϵµÄ¶ÀÁ¢×é·ÖÊý£¬ÏàÊý¼°×ÔÓɶȷֱðΪ( ).

8.ÔÚҺ̬ÍêÈ«»¥ÈܵÄÁ½×é·ÖA¡¢B×é³ÉµÄÆøÒºÆ½ºâϵͳÖУ¬Íâѹһ¶¨Ê±£¬ÓÚ¸ÃÆøÒºÆ½ºâϵͳÖмÓÈë×é·ÖB(l)ºó£¬ÏµÍ³µØ·ÐµãϽµ£¬Ôò¸Ã×é·ÖÔÚÆ½ºâÆøÏàÖеÄ×é³ÉyB( )ËüÔÚÒºÏàÖеÄ×é³ÉxB

9.A(l)ºÍB(l)ÐγÉÀíÏëҺ̬»ìºÏÎÔÚζÈTÏ£¬´¿A(l)µÄ±¥ºÍÕôÆûѹΪPA*,´¿B(l)µÄ±¥ºÍÕôÆûѹΪPB*=5PA*¡£ÔÚÒ»¶¨Î¶ÈÏ£¬½«A(l)ºÍB(l)»ìºÏ³ÉÒ»ÆøÒºÆ½ºâϵͳ£¬²âµÃÆä×ÜѹΪ2PA*,´ËʱƽºâÆøÏàÖÐBµÄĦ¶û·ÖÊýyB=( ) 10.¶ÔÈý×é·ÖÏàͼ£¬×î¶àÏàÊýΪ£¨ £©£»×î´ó×ÔÓɶÈÊýΪ£¨ £©£»ËüÃÇ·Ö±ðÊÇ£¨ £©µÈÇ¿¶È±äÁ¿¡£

11.ÔÚζÈTÏ£¬A¡¢BÁ½×é·ÖÔÚÒºÏàÍêÈ«»¥ÈÜ£¬¶øÇÒËüÃǵı¥ºÍÕôÆøÑ¹·Ö±ðΪPA*ÓëPB*£¬ÇÒPA*>PB*.ÔÚÒ»¶¨Î¶ÈÏ£¬ÓÉA¡¢B×é³ÉµÄÆøÒºÆ½ºâϵͳ£¬µ±ÏµÍ³×é³ÉXB<0.3ʱ£¬ÍùϵͳÖмÓÈëB(l)ÔòϵͳѹÁ¦Ôö´ó£»·´Ö®£¬µ±ÏµÍ³×é³ÉXB>0.3ʱ£¬ÍùϵͳÖмÓÈëB(l)ÔòϵͳѹÁ¦½µµÍ£¬ÕâÒ»½á¹û˵Ã÷ϵͳ¾ßÓУ¨ £©ºã·Ðµã¡£ 12.ÔÚ1000KÏ£¬¶à×é·Ö¶àÏàÆ½ºâϵͳÖÐÓÐC(ʯ£¬CO2 (g), CO(g) ¼°O2 (g)¹²´æ£¬¶øÇÒËüÃÇ¼ä´æÔÚÒÔÏ»¯Ñ§·´Ó¦£º

C(ʯī) + O2 (g) = CO2 (g) C(ʯī) + 1/2O2 (g) = 1/2CO(g) CO(g) + 1/2O2 (g) = CO2 (g) C(ʯī) + CO2 (g) = 2CO(g)£¬Ôò´ËƽºâϵͳµÄ×é·ÖÊýC=£¨ £©£¬P=£¨ £©£¬F=£¨ £© 13.Ò»°ãÓлúÎï¿ÉÒÔÓÃË®ÕôÆøÕôÁó·¨Ìá´¿,µ±ÓлúÎïµÄ( )ºÍ( )Ô½´óʱ,Ìá´¿Ò»¶¨ÖÊÁ¿ÓлúÎïÐèÓõÄË®ÕôÆøÔ½ÉÙ.

14.Ò»¸ö´ïµ½Æ½ºâµÄϵͳÖÐÓÐZnO(s),Zn(s),CO(g),CO2(g),C(s)ÎåÖÖÎïÖÊ,Ôò¸ÃϵͳµÄ¶ÀÁ¢×é·ÖÊýΪ( ),×ÔÓɶÈÊý( ). Èý¡¢ÅжÏÌâ

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12.ºã·Ð»ìºÏÎïÓ뻯ºÏÎïÒ»Ñù,¾ßÓÐÈ·¶¨µÄ×é³É¡£( )

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14.¶þ×é·Ö·Ðµã-×é³ÉͼÖÐ,´¦ÓÚ×î¸ß»ò×îµÍºã·ÐµãʱµÄ״̬,ÆäÌõ¼þ×ÔÓɶÈÊýF¡¯=0.( ) Ñ¡ÔñÌâ´ð°¸:

1.A;2.C;3.B;4.B;5C;6.C;7.B;8.C;9.C;10.B;11.D;12.A;13.D;14.B;15.C;16.A; 17.C Ìî¿ÕÌâ´ð°¸:

1. C=2£¬P=3£¬F=1;2. Ò»ÖÖ;3. C=1£¬F=1;4. 2£»3;5. Äܹ»Î¬³ÖϵͳԭÓÐÏàÊý¶ø¿ÉÒÔ¶ÀÁ¢¸Ä±äµÄ±äÁ¿Êý£¬F=C- P+2;6. F=4;7. C=2£¬P=3£¬F=1;8.>;9.0.625;10. 5£¬4£»Î¶ȡ¢Ñ¹Á¦¼°Á½¸ö×é³É;11.×î¸ßºã·Ðµã;12.C=2£¬P=2£¬F=1;13.±¥ºÍÕôÆøÑ¹,Ħ¶ûÖÊÁ¿;14.3,1 ÅжÏÌâ´ð°¸:

1. ¡Ì;2. ¡Ì; 3. ¡Ì; 4. ¡Á;5. ¡Ì;6; ¡Ì; 7.¡Á;8. ¡Ì;9. ¡Ì;10. ¡Ì;11. ¡Á;12. ¡Á;13 ¡Ì;14. ¡Ì ËÄ¡¢¼ÆËãÌâ

1.Ö¸³öÏÂÁÐÆ½ºâϵͳÖеÄ×é·ÖÊýC,ÏàÊýP¼°×ÔÓɶÈÊý. (1)I2(s)ÓëÆäÕôÆø³Éƽºâ;

(2)CaCO3(s)ÓëÆä·Ö½â²úÎïCaO(s)ºÍCO2(g)³Éƽºâ;

(3)NH4HS(s)·ÅÈëÒ»³é¿ÕµÄÈÝÆ÷ÖÐ,²¢ÓëÆä·Ö½â²úÎïNH3(g)ºÍH2S(g)³Éƽºâ; (4)È¡ÈÎÒâÁ¿µÄNH3(g)ºÍH2S(g)ÓëNH4HS(s)³Éƽºâ;

(5)I2×÷ΪÈÜÖÊÔÚÁ½²»»¥ÈÜÒºÌåH2OºÍCCl4Öдﵽ·ÖÅ䯽ºâ(Äý¾Ûϵͳ). Please find C=£¿P=? and f =? in the following equilibrium systems. (1)I2(s) is equilibrium with it¡¯s vapor ;

(2)CaCO3(s) is partially decomposed in equilibrium with CaO(s) and CO2(g);

(3)NH4HS(s) is partially decomposed in equilibrium with NH3(g) and H2S(g) in a vacuum container;