0359 0.1 mol/L (NH4)2HPO4ÈÜÒºµÄÖÊ×ÓÌõ¼þʽÊÇ____________________________________ ___________________________¡£ 0.1 mol/L H2SO4ÈÜÒºµÄÖÊ×ÓÌõ¼þʽÊÇ_______________________________¡£ 0360 ij(NH4)2CO3ÈÜÒºc[(NH4)2CO3] = c mol/L,ÆäÎïÁÏÆ½ºâʽΪ______________________ _____________________¡£ 0361 1. ½«20mL 0.10mol/L NaOHÈÜÒººÍ10 mL 0.10 mol/L H2SO4»ìºÏ, ËùµÃÈÜÒºµÄÖÊ×ÓÌõ¼þʽÊÇ_________________________________________________¡£ 2. ½«20 mL 0.10 mol/L HCl ºÍ 20 mL 0.05 mol/L Na2CO3»ìºÏ, ËùµÃÈÜÒºµÄÖÊ×ÓÌõ¼þʽÊÇ_________________________________________________¡£ 0362 ijNH4HC2O4ÈÜÒºc(NH4HC2O4) = c mol/L,ÆäÎïÁÏÆ½ºâʽΪ_________________ _____________; µçºÉƽºâʽΪ_________________________________________¡£ 0363 ij(NH4)2HPO4ÈÜÒºc[(NH4)2HPO4] = c mol/L,ÆäÎïÁÏÆ½ºâʽΪ_______________ _______________________________; µçºÉƽºâʽΪ__________________________________ __________________________¡£ 0364 ¼ÆËãÒÔÏÂÈÜÒºµÄ[H+]: (1) 0.10 mol/L NH4CNÈÜÒº (2) 0.10 mol/L NH4A ÈÜÒº ÒÑÖª pKa(NH4+) = 9.26, pKa(HCN) = 9.21, pKa(HA) = 1.30¡£ 0365 ¼ÙÉèijËá¼îָʾ¼ÁHInµÄ±äÉ«pH·¶Î§Îª2.60, Èô¹Û²ìµ½¸ÕÏÔËáʽ(HIn)ɫʱ±ÈÂÊ[HIn]/[In-]ºÍ¼îʽ(In-)ɫʱ[In-]/[HIn]ÊÇÏàͬµÄ¡£µ±Ö¸Ê¾¼Á¸ÕÏÔËáÉ«»ò¼îɫʱ,HIn»òIn-ÐÎÌåËùÕ¼µÄ°Ù·Ö±ÈΪ¶àÉÙ? 0366 pKa(HCOOH) = 3.77, pKb(HCOO-) = _________; NaOHµÎ¶¨HCOOH·´Ó¦µÄKt = ______________; HClµÎ¶¨HCOO-·´Ó¦µÄKt = ______________¡£ 0401 ½«1.0 mol/L NaAcÓë0.10 mol/L H3BO3µÈÌå»ý»ìºÏ,ËùµÃÈÜÒºpHÊÇ--------------( ) [pKa(HAc) = 4.74, pKa(H3BO3) = 9.24] (A) 6.49 (B) 6.99 (C) 7.49 (D) 9.22 0402 ÓÃNaOHµÎ¶¨Ä³Ò»ÔªËáHA,ÔÚ»¯Ñ§¼ÆÁ¿µãʱ,[H+]µÄ¼ÆËãʽÊÇ--------------------------( ) (A) Ka?c(??) (B) Ka?KW (D) Ka?c(??)c(??) ?c(?) (C) Ka?KW c(??)0403 EDTAµÄpKa1~pKa6·Ö±ðÊÇ0.9,1.6,2.0,2.67,6.16ºÍ10.26¡£EDTA¶þÄÆÑÎ(Na2H2Y)Ë®ÈÜÒºpHÔ¼ÊÇ---------------------------------------------------------------------------------------------------( ) (A) 1.25 (B) 1.8 (C) 2.34 (D) 4.42 0404 0.10 mol/L HClºÍ1.0 mol/L HAc(pKa = 4.74)»ìºÏÒºµÄpHΪ---------------------------( ) (A) 2.37 (B) 1.30 (C) 1.00 (D) 3.37 0405 pH=1.00µÄHClÈÜÒººÍpH=13.00 µÄ NaOH ÈÜÒºµÈÌå»ý»ìºÏ,ËùµÃÈÜÒºµÄpHÊÇ-------------------------------------------------------------------------------------------------------------( ) (A) 14 (B) 12 (C) 7 (D) 6 0406 ÒÑÖªH3PO4µÄKa1 = 7.6¡Á10-3, Ka2 = 6.3¡Á10-8, Ka3 = 4.4¡Á10-13,ÈôÒÔNaOHÈÜÒºµÎ¶¨H3PO4ÈÜÒº,ÔòµÚ¶þ»¯Ñ§¼ÆÁ¿µãµÄpHԼΪ-------------------------------------------------------( ) (A) 10.7 (B) 9.7 (C) 7.7 (D) 4.9 0407 ½«µÈÌå»ýµÄpH=3µÄHClÈÜÒººÍpH=10µÄNaOHÈÜÒº»ìºÏºó,ÈÜÒºµÄpHÇø¼äÊÇ-( ) (A) 3~4 (B) 1~2 (C) 6~7 (D) 11~12 0408 0.10 mol/L NH2OH(ôǰ·)ºÍ0.20 mol/L NH4ClµÈÌå»ý»ìºÏÒºµÄpHÊÇ--------------( ) [pKb(NH2OH) = 8.04, pKb(NH3) = 4.74] (A) 6.39 (B) 7.46 (C) 7.61 (D) 7.76 0409 ÒÔÏÂÈÜҺϡÊÍ10±¶Ê±pH¸Ä±ä×îСµÄÊÇ--------------------------------------------------( ) (A) 0.1 mol/L NH4AcÈÜÒº (B) 0.1 mol/L NaAcÈÜÒº (C) 0.1 mol/L HacÈÜÒº (D) 0.1 mol/L HClÈÜÒº 0410 ÒÔÏÂÈÜҺϡÊÍ10±¶Ê±pH¸Ä±ä×î´óµÄÊÇ--------------------------------------------------( ) (A) 0.1 mol/L NaAc-0.1 mol/L HAcÈÜÒº (B) 0.1 mol/L NH4Ac-0.1 mol/L HAcÈÜÒº (C) 0.1 mol/L NH4AcÈÜÒº (D) 0.1 mol/L NaAcÈÜÒº 0411 ½«Ï±íÖÐËÄÖÖÈÜÒºÒÔˮϡÊÍ10±¶,ÇëÌîдÆäpH±ä»¯´óСµÄ˳Ðò,±ä»¯×î´óÕßΪ¡°1¡±¡¢×îСÕßΪ¡°4¡±¡£ ÈÜÒº ˳Ðò 0.1 mol/L HAc 0.1 mol/L HAc + 0.1 mol/L NaAc 1.0 mol/L HAc + 1.0 mol/L NaAc 0.1 mol/L HCl 0412 1.0 mol/L NH4HF2ÈÜÒºµÄpHÊÇ-------------------------------------------------------------( ) [pKa(HF) = 3.18, pKb(NH3) = 4.74] (A) 1.59 (B) 3.18 (C) 6.22 (D)9.26 0413 ½ñÓÐÈýÖÖÈÜÒº·Ö±ðÓÉÁ½×é·Ö×é³É: (a) 0.10 mol/L HCl-0.20 mol/L NaAcÈÜÒº (b) 0.20 mol/L HAc-0.10 mol/L NaOHÈÜÒº (c) 0.10 mol/L HAc-0.10 mol/L NH4AcÈÜÒº ÔòÈýÖÖÈÜÒºpHµÄ´óС¹ØÏµÊÇ-------------------------------------------------------------------( ) [ÒÑÖªpKa(HAc) = 4.74, pKa(NH4+) = 9.26] (A) a