´óѧÎÞ»ú»¯Ñ§ÊÔÌ⼯ - - ÕÅ׿µÂ ÏÂÔØ±¾ÎÄ

µÚËÄÕ µçÀëÆ½ºâ

1. ÅðËáÊÇÒ»ÔªÈõËá¡£ÔÚijζÈÏ£¬ÔÚ0.1mol?dm3 µÄH3BO3ÖУ¬[H+]=1.05?105¡£¼ÆËãÔÚ

£­

£­

´ËζÈÏ£¬ÅðËáµÄµçÀë³£Êý¡£ 2. ÒÑÖª0.1 mol?dm 3. 0.2 mol?dm

£­3

£­3

µÄMOHÈÜÒºÔÚ25?CµÄÀë½â¶ÈΪ2%£¬Çó´Ë¼îµÄÀë½â³£ÊýKb¡£

£­

£­

µÄ¼×ËáÈÜÒºµÄµçÀë¶ÈΪ2.95%£¬ÇóËüµÄµçÀëÆ½ºâ³£Êý¡£

£­3

4. ½«0.2 mol?dm

µÄ°±Ë®¼ÓˮϡÊÍÖÁ0.05 mol?dm3£¬ÎÊOH Àë×ÓµÄŨ¶ÈÓÐʲô±ä»¯£¿

£­3

5. ¼ÆËã0.0010 mol?dm

µÄ´×ËáÈÜÒºµÄH+Àë×ÓŨ¶È¡££¨ÒÑÖª´×ËáµÄKa=1.8?105)

£­

6. ¼ÆËãÏÂÁи÷ÖÖÇé¿öµÄpH£º (1) 200cm3ÈÜÒºÖк¬20g NaOH¡£

(2) 1500cm3Ë®ÖмÓÈë0.5cm310%±ÈÖØÎª1.05µÄÑÎËá¡£ (3) 10cm3ÈÜÒºÖк¬ÓÐ82mgµÄNaAc¡£

(4) 1dm3ÈÜÒºÖк¬ÓÐ12gNaHSO4¡££¨ÒÑÖªH2SO4µÄK2=1.26?102)

£­

7. ¼ÆËã0.010 mol?dm 8. ÓÃ0.10 mol?dmÈÜÒºµÄpH¡£

£­3

£­3

¼×ËáÈÜÒºÖи÷·Ö×ÓºÍÀë×ÓµÄŨ¶È£¿£¨Ka=1.8?104)

£­

£­3

µÄNaOHÈÜÒºµÎ¶¨50cm3¡¢0.20mol?dm

µÄHFÈÜÒº£¬ÊÔÇóÏÂÁÐÇé¿öÏÂ

(1)µ±NaOHÈÜÒº¼ÓÈë5cm3ʱ£» (2) µ±HFÒÑÖкÍÁËÒ»°ë£» (3) Ôڵȵ±Á¿Ê±¡£ 9. H2SµÄK1Ϊ9.1?108£¬K2Ϊ1.1?10

£­

£­12

¡£ÔÚpH=8ʱ[H2S]/[HS?]µÄ±ÈֵΪ¶àÉÙ£¿Èç¹ûÔÚ1

atmÏ£¬Áò»¯ÇâµÄÈܽâ¶ÈΪ0.1mol?dmÉÙ£¿

£­3

(ÔÚËáÐÔÈÜÒºÖУ©£¬ÎÊÔÚpH=8ʱ£¬ËüµÄÈܽâ¶ÈΪ¶àµÄNH3?H2OÈÜÒº£¬ÏÖÓÃ0.1mol?dm3 ÑÎËáµÎ¶¨¡£¼Æ

£­

10. ×¶ÐÎÆ¿ÖÐÊ¢·Å20cm3¡¢0.1 mol?dmË㣺

£­3

(1)µ±µÎÈë10cm3 ÑÎËáºó£¬»ìºÏÈÜÒºµÄpH£» (2)µ±µÎÈë20cm3 ÑÎËáºó£¬»ìºÏÈÜÒºµÄpH£» (3)µ±µÎÈë30cm3 ÑÎËáºó£¬»ìºÏÈÜÒºµÄpH¡£

11. ¼ÆËãÏÂÁлìºÏÈÜÒºµÄpHÖµ£¨¼Ù¶¨»ìºÏºó×ÜÌå»ýµÈÓÚ¸÷»ìºÏÌå»ýÖ®ºÍ£©£º (1) 60cm3µÄ0.1mol?dm (3) 50cm3µÄ0.1mol?dm 12. ¼ÆËã0.20mol?dm

£­3

£­3£­

¼×ËáÓë40cm3µÄ0.15mol?dm

£­3

ÇâÑõ»¯ÄÆÈÜÒº£»

£­3

(2) 50cm3µÄ0.1mol?dm3NaCNÈÜÒºÓë50cm3µÄ0.1mol?dm

£­3£­

£­£­

ÑÎË᣻

ÑÎËáÓë50cm3µÄ0.08mol?dm3NaOHÈÜÒº£»

(4) 50cm3µÄ0.1mol?dm3HAcÓë50cm3µÄ0.12mol?dm3NaOHÈÜÒº¡£

µÄNa2SÈÜÒºµÄpHΪ¶àÉÙ£¿

µÄNH4NO2ÈÜÒºµÄpH¡££¨Ka=4.5?104, Kb=1.8?105£©

£­

£­

13. ÊÔ¼ÆËã0.1mol?dm

£­3

14. ½«Ä³Ò»ÔªÈõËáÈÜÓÚδ֪Á¿Ë®ÖУ¬ÓÃһδ֪Ũ¶ÈµÄÇ¿¼îÈÜҺȥµÎ¶¨¡£µ±ÓÃÈ¥3.05cm3Ç¿¼îʱ£¬ÈÜÒºpH=4.00£»ÓÃÈ¥12.91ml¸ÃÇ¿¼îÈÜҺʱ£¬ÈÜÒºpH=5.0¡£ÎʸÃÈõËáµÄµçÀë³£ÊýΪ¶àÉÙ£¿£¨Ìå»ý¿ÉÒԼӺͣ©

29

15. ÒÑ֪ij´×ËáÄÆÈÜÒºµÄpH=8.52£¬Çó500cm3¸ÃÈÜÒºÖк¬CH3COONa¶àÉÙ¿Ë£¿ 16. ¼ÆËãŨ¶ÈΪ1 ? 107 mol?dm

£­

£­

£­

£­3

ÑÎËáÈÜÒºµÄpH¡£

£­

£­

£­

£­3

17. Ò»ÖÖËáHAµÄKa=104£¬ÁíÒ»ÖÖËáHBµÄKa=108£¬¼ÙÈô½«1.00 mol?dm3 HBºÍ1.00 mol?dm3 Na+A?»ìºÏ½«»á·¢Éúʲô·´Ó¦£¿Èô½«1.00mol?dm3HAÓë1.00mol?dmÄØ?

18. ÔÚ1dm3±¥ºÍµÄH2SÈÜÒºÖмÓÈë1.56g Na2S ,¼ÆËãÕâÈÜÒºÖÐ[S2?]ºÍ[H+]¸÷Ϊ¶àÉÙ£¿ 19. ΪҪÅä³ÉpH=5.00µÄ»º³åÈÜÒº£¬ÔòÐè0.20 mol?dm3 µÄ´×ËáºÍ0.20 mol?dm3 ´×ËáÄÆÈÜ

£­

£­

µÄNaB»ìºÏ

ÒºµÄÌå»ý±ÈΪ¶àÉÙ£¿

20. °ÑÂÈ»¯ÇâÆøÌåͨÈë1.0dm3º¬0.010 molµÄ´×ËáºÍ0.010 molµÄ´×ËáÄÆµÄ»ìºÏÈÜÒºÖУ¬Ê¹ÈÜÒºµÄpH=3.0£¬ÎÊ£º±ØÐëͨÈë¶àÉÙĦ¶ûµÄÂÈ»¯ÇâÆøÌ壿

21. ÐèÒª¶àÉÙÁ¢·½ÀåÃ×µÄ6.0 mol?dm3 ÑÎËáÈÜÒº¼ÓÈëµ½100cm3¡¢0.1 mol?dm3 ´×ËáÄÆÈÜÒº

£­

£­

ÖУ¬²ÅÄÜʹ´ËÈÜÒºµÄpH=4.25 ?

22. ¶¯ÂöѪҺÖÐÈܽâµÄCO2ÈÜҺΪ2.6?10 ÒÑÖª£ºK1=7.9 ?105, K2=1.6 ?10

£­

£­2

mol?dm3 ,´ËѪҺµÄpH=7.43¡£¼ÙÉè´ËѪҺÖÐ

£­

CO2ÒÔH2CO3µÄÐÎʽ´æÔÚ£¬ÊÔ¼ÆË㶯ÂöѪҺÖÐHCO3?µÄŨ¶È¡£

£­12

)

23. ÓÉÈËÌå×éÖ¯Ñõ»¯Ëù²úÉúµÄCO2£¬¾­ÑªÒºÁ÷µ½·Î¡£ÔÚѪҺÖÐCO2ÒÔH2CO3ºÍHCO3?Á½ÖÖÐÎʽ´æÔÚ¡£ÈôѪҺÖÐpH=7.4£¬ÇóÓжàÉÙCO2ÒÔʲôÐÎʽÁ÷Èë·ÎÖжøÅųö£¿

24. Óð±Ë®ºÍÂÈ»¯ï§ÖƳÉ200cm3£¬pH=9.49µÄ»º³åÈÜÒº£¬ÎªÊ¹¼ÓÈë1.0mmolµÄH+Àë×Ó»òOH?Àë×Ӻ󣬸ûº³åÈÜÒºµÄpH±ä»¯²»´óÓÚ0.12¸öpHµ¥Î»£¬ÇóÐè¶àÉÙ¿ËNH4ClºÍ¶àÉÙÁ¢·½ÀåÃ×1.0 mol?dm

£­

£­3

µÄ°±Ë®£¿

£­

25. ÒÑ֪ij»º³åÈÜÒºÊÇÓÉÈõËáHA (Ka=5?105) ºÍËüµÄÇ¿¼îÑÎ×é³É,ÆäÖÐHAµÄŨ¶ÈΪ0.25mol?dm3 ,100cm 3´Ë»º³åÈÜÒºÖмÓÈë5mmolµÄNaOHºó,ÈÜÒºµÄpH±ä³É5.6,ÊÔÇóÔ­À´»º³åÈÜÒºµÄpH¡£

26. ÓûÖÆ±¸pH=5µÄ»º³åÈÜÒº£¬ÏÖÑ¡ÓÃÏÂÁÐÈýÖÖÒ»ÔªÈõËáºÍËüÃǵÄÑΣ¬ËüÃǵĵçÀëÆ½ºâ³£Êý·Ö±ðΪ£º(1) Ka=2?105£¬ (2) Ka=5?105£¬ (3) Ka=5?106

£­

£­

£­

ͨ¹ý¼ÆËã˵Ã÷ΪÁËÖÆ±¸ÕâÒ»»º³åÈÜÒº£¬Ó¦È¡µÄÿÖÖËáºÍËüµÄÑεÄŨ¶È±È¸÷Ϊ¶àÉÙ£¿ 27. ÒÑÖªHFµÄÀë½â³£ÊýΪ6.71?104 ,¼ÆËã¶àÉÙ¿ËNaF¼ÓÈë0.100dm3¡¢0.5mol?dm3HFÈÜ

£­

£­

ÒºÖУ¬Ê¹H3O+Ũ¶ÈµÈÓÚ2.00 ? 103mol?dm3£¨¼ÙÉèNaF¼ÓÈëÈÜÒºÖУ¬¶ÔÈÜÒºÌå»ýÎÞÓ°Ï죩¡£

£­

£­

28. ÒÑÖªHFµÄÀë½â³£ÊýΪ6.71? 104£¬ÎÊÐèÒª¼Ó¶àÉÙÌå»ýµÄË®µ½50.0cm3¡¢0.270mol?dm

£­

£­3

HF

ÈÜÒºÖУ¬Ê¹H3O+Àë×ÓŨ¶ÈΪԭÀ´µÄ¶þ·ÖÖ®Ò»£¨Ìå»ý¿ÉÒԼӺͣ©¡£

29. ¼ÙÈôÒªµÃµ½pH=1.000µÄÁòËáÈÜÒº£¬ÄÇô´ËÁòËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈÊǶàÉÙ£¿£¨K2=1.26? 102£©

£­

30. ijŨ¶ÈµÄNaHSO4ÈÜÒº£¬ÆäpH=1.26£¬ÊÔÇó¸ÃNaHSO4ÈÜÒºµÄŨ¶È¡£

31. ÒÑÖªpH=1.00µÄ1dm3ÁòËáÈÜÒº£¬¼ÓÈë¶àÉÙÌå»ýµÄË®ºó£¬¿ÉʹÈÜÒºµÄpH=2.00£¿£¨Ìå»ý¿ÉÒԼӺͣ©

30

32. ¶àÉÙÁ¢·½ÀåÃ×µÄŨH2SO4£¨18mol?dm3)¼ÓÈëµ½1dm3Ë®ÖУ¬¿ÉµÃµ½pH=3.00µÄÈÜÒº¡£

£­

£¨Ìå»ý¿ÉÒԼӺͣ©

33. ½«10.0cm3µÄ1.00mol?dm3 H2SO4ºÍ30.0cm3µÄ1.00mol?dm3 K2SO4»ìºÏ£¬¼ÙÉèÌå»ý¿É

£­

£­

ÒԼӺͣ¬ÎʸûìºÏÈÜÒºµÄH3O+µÄŨ¶ÈÊǶàÉÙmol?dm3£¿

£­

34. ¶ÔÓÚÒ»¸öÈýÔªËáH3AsO4£¬Àë½â³£Êý·Ö±ðΪK1=2.5 ?104, K2=5.6 ? 108, K3=3?10

£­

£­

£­13

£¬

Îʶà´óµÄH3AsO4Ũ¶È²Å»áµÃµ½[AsO43?]=4? 10K2=6.2 ?108£¬K3=1 ?10

£­

£­12

£­18

mol?dm3£¿

£­

£­

35. °Ñ0.100molH3PO4ºÍ0.200molNaH2PO4ÈÜÓÚË®, Åä³É1dm3ÈÜÒº¡£ÒÑÖªK1=7.5?103£¬

£¬ÊÔ¼ÆËã´ËÈÜÒºÖÐH3PO4¡¢H2PO4?¡¢HPO42?¡¢PO43?¡¢H3O+ºÍNa+

H3O+ + HCO3 K1=4.16 ?107

£­

£­

µÄŨ¶È¡£

36. ÒÑÖª CO2 + 2H2O HCO3? + H2O

£­

H3O+ + CO32? K2=4.84 ?10

£­

£­

£­11

ÊÔÇó0.034mol?dm3 CO2 ÈÜÒºÖÐH3O+,CO32?ºÍHCO3?µÄŨ¶È¡£

37. ÒÑÖªÒ»Èõ¼îBOHµÄÀë½â³£ÊýΪ1.50 ?108¡£¼ÙÉè1.25 ?103molµÄBCl£¨ÎªÒ»Ç¿µç½âÖÊ£©ºÍ1.25? 103mol NaOHÖÆ³É1dm3ÈÜÒº£¬Çó´ËÈÜÒºÖУ¬B+¡¢OH? ºÍBOHµÄŨ¶È£¿

£­

38. ¼ÙÉè1.00dm3 µÄ0.100mol?dm3 HCl ºÍ1.00dm3 µÄ0.1000mol?dm3 Na2SO4»ìºÏ£¬Çó´Ë

£­

£­

ÈÜÒºÖÐH3O+¡¢SO42?¡¢HSO4?Àë×ÓµÄŨ¶È¸÷Ϊ¶àÉÙ£¿£¨¼ÙÉèÈÜÒºµÄÌå»ý¿ÉÒԼӺͣ¬K2=1.26? 10

£­2

)

39. ¸ù¾ÝHAc¡¢NH3?H2O¡¢H2C2O4¡¢H3PO4ËÄÖÖËá¼îµÄµçÀë³£Êý£¬Ñ¡È¡ÆäÖÐÊʵ±µÄËá¼°Æä¹²éî¼îÀ´ÅäÖÆpH=7.51µÄ»º³åÈÜÒº£¬Æä¹²éîËá¼îµÄŨ¶È±ÈÓ¦ÊǶàÉÙ£¿

40. °Ñ10.0cm3 pH =1.500µÄH2SO4ºÍ20.0cm3 pH =1.500µÄNaHSO4»ìºÏ£¨Ìå»ý¿ÉÒԼӺͣ©ÎÊ»ìºÏºóÈÜÒºµÄ×îÖÕpHΪ¶àÉÙ£¿

41. ÓÐ0.250 dm3º¬ÓÐ0.350mol?dm3µÄ´×ËáºÍ0.350 mol?dm3µÄ´×ËáÄÆÈÜÒºµÄ»º³åÈÜÒº¡£Èô

£­

£­

¼ÓÈë30.0cm3µÄ0.100 mol?dm3 HClÓÚ´Ë»º³åÈÜÒºÖУ¬ÊÔÇóÈÜÒºpHµÄ±ä»¯£¿£¨Ka=1.8? 105)

£­

£­

42. ÓÐ80.0cm3 µÄ0.169 mol?dm3 NH3 ºÍ0.183 mol?dm

£­

£­

£­3

µÄNH4ClµÄ»º³åÈÜÒº£¬Èô¼ÓÈë

£­

£­3

10.0cm3 0.100 mol?dm3 HCl£¬ÎÊpH ÊÇÈçºÎ±ä»¯µÄ£¿£¨Kb=1.81? 105,Ìå»ý¿ÉÒԼӺͣ© 43. ÓÐ1dm3 µÄ6.0 mol?dm

£­3

NH3ÈÜÒº¡£ÎʱØÐë¼ÓÈë¶àÉÙÁ¢·½ÀåÃ×1.0 mol?dm

£­

£­

NH4Cl£¬

²ÅÄܵõ½pH=9.00 µÄ»º³åÈÜÒº¡££¨Ìå»ý¿ÉÒԼӺͣ©

44. ¶àÉÙÁ¢·½ÀåÃ× 1.00 mol?dm3 µÄNaOH ¼ÓÈë100.0cm3 µÄ1.00 mol?dm3 µÄH2SO4 ²úÉúµÄ»º³åÈÜÒº pH=1.900£¿£¨Ìå»ý¿ÉÒԼӺͣ©

45. °Ñ10.0cm3µÄ0.100 mol?dm3 H2SO4¼ÓÈëµ½0.100dm3 º¬0.150 mol?dm3µÄNaHSO4ºÍ

£­

£­

0.15mol?dm3Na2SO4µÄ»º³åÈÜÒºÖУ¬ÎÊpHÊÇÈçºÎ±ä»¯µÄ£¿£¨Ìå»ý¿ÉÒԼӺͣ©

£­

46. ÒÑÖªÒ»±êÇ©ÉÏд×Å0.0200 mol?dmµÄŨ¶È¡££¨Ka = 4.5? 104)

£­

£­3

µÄHNO2ÈÜÒº£¬ÊÔÇó´ËÈÜÒºÖÐH3O+¡¢NO2? ºÍHNO2

£­

47. ¼ÙÉè1.08g HClO2¼Óµ½427cm3µÄ0.0150 mol?dm3 NaClO2ÈÜÒºÖУ¨Ìå»ý²»·¢Éú±ä»¯£©£¬

31

¼ÆËãH3O+¡¢ClO2?ºÍHClO2µÄ×îÖÕŨ¶È¡££¨Ka=1.1 ?102£©

£­

48. ijÉú»¯ÊµÑéÊÒÓÐpHΪ7.50¶¯ÂöѪÑùÆ·20.00cm3

(1)ÈôÔÚ298K¡¢101kPaÆøÑ¹ÏÂËữ´ËÑùÆ·ºó£¬ÄÜÊͷųö12.2cm3µÄCO2£¬ÇóѪҺÖÐCO2(CO2+H2CO3)ºÍHCO3?µÄŨ¶È¡£

(2)ÒÑÖªÔÚ101kPa CO2µÄÆøÑ¹Ï£¬±»CO2±¥ºÍµÄ¶¯ÂöѪҺÖк¬0.031mol CO2(CO2+H2CO3)£¬ÔòÉÏÊö¶¯ÂöѪҺÑùÆ·ÉÏ·½CO2µÄ·ÖѹÊǶàÉÙ£¿ 49. ¸ù¾ÝPauling¹æÔò£¬¹À¼ÆÏÂÁи÷ËáµÄpK1£º

(1) H2CrO4 (2) HBrO4 (3) HClO (4) H5IO6 (5) HSO3F (6) H3AsO4

50. ÔÚҺ̬HFÖУ¬ÏÂÁи÷ÎïÖÊÊÇÒÔËáµÄÐÎʽ×÷Óû¹ÊÇÒÔ¼îµÄÐÎʽ×÷Óã¬Ð´³ö·´Ó¦·½³Ìʽ˵Ã÷Ö®¡£

(1) BF3 (2) SbF5 (3) H2O (4) CH3COOH (5) C6H6

51. ÒÑÖªH2SO4µÄ×ÔżµçÀëµÄÀë×Ó»ý³£ÊýΪ2.8? 104£¬ÊÔ¼ÆËã´¿H2SO4Öи÷Àë×ÓµÄŨ¶È¡£

£­

52. ÒÑÖª·´Ó¦£º HCl + HAc

H2Ac+ + Cl? (ÔÚ±ù´×ËáÈÜÒºÖнøÐУ©µÄƽºâ³£ÊýΪ2.8 ?109,ÓÖÖªHAc

£­

£­15

µÄ×ÔżµçÀëºóµÄÀë×Ó»ý³£ÊýΪ3.6? 10H2Ac+¡¢Cl?¡¢Ac?µÄŨ¶È¡£

£¬ÊÔ¼ÆËã1.0? 104 mol?dm

£­

£­

£­3

µÄHClµÄHAcÈÜÒºÖС¢

53. ÇâÑõ»¯Òø£¨AgOH£©²»ÈÜÓÚË®£¨Ksp=1 ?108£©¡£ÊÔÉè¼ÆÒ»ÖÖ¼òµ¥µÄ¶¨ÐÔʵÑéÀ´È·¶¨AgOHÊÇÇ¿¼î»¹ÊÇÈõ¼î£¿

54. д³öÏÂÁи÷ËáµÄ¹²éî¼îµÄʽ×Ó£º

(1) H3PO4 (2) HSO4? (3) SH? (4) Cr(H2O)63+ (5) H2AsO4? 55. д³öÏÂÁи÷¼îµÄ¹²éîËáµÄʽ×Ó£º

(1) C2H5NH2 (2) H4IO6? (3) B(OH)4? (4) VO(OH)+ 56. Ö¸³öÏÂÁи÷·Ö×Ó»òÀë×ÓÖÐÄÄЩÊÇ·Ò×˹ËᣬÄÄЩÊÇ·Ò×˹¼î£¿ (1) AlCl3 (2) OH? (3) Br? (4) H2O (5) NO+ (6) CO2 (7) NH3 (8) Fe3+ (9) (CH3)2S (10) SbF5 57. ÊÔÖ¸³öNH3ºÍNF3µÄ·Ò×˹¼îÐÔÄÄÒ»¸öÇ¿£¿ÊÔ¼ÓÒÔ½âÊÍ¡£ 58. Ó÷Ò×˹Ëá¼îÀíÂÛ½âÊÍÏÂÁз´Ó¦ÎªÊ²Ã´»á·¢Éú£¿ (1) BF3 + F? ? BF4? (2) S + SO32? ? S2O32? (3) AlCl3 + Cl? ? AlCl4?

(4) Co2+ + 6NH3 ? Co(NH3)62+

59. ¼ºÖªH3PO2ºÍH3PO3µÄK1ֵΪ102£¬ÊÔ¸ù¾ÝPaulingº¬ÑõËá¹æÔò£¬ÍƳöH3PO2ºÍH3PO3

£­

·Ö×ÓÖеļüÁ¬·½Ê½¡£

60. ´¿ÁòËáµÄÕ³¶È·Ç³£´ó£¬ÎªÊ²Ã´´¿ÁòËáÖÐH3SO4+ºÍHSO4Àë×ÓµÄÇ¨ÒÆËÙ¶È¿ÉÒÔÓëË®ÖеÄ

£­

32