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ÔÙ¼ÆËãm({h1},{h2})£º

m({h1},{h2})=(0.6¡Á0.3, 0.6¡Á0.5)=(0.18, 0.3) ÓÚÊÇ

Bel(H)=m(?)+m({h1})+m({h2})+m({h1,h2})

=0+0.18+0.3+0=0.48 Pl(H)==1-Bel(~H)=1-0=1 ×îºóµÃ

f1(H)=Bel(H)+|H|/|U|(Pl(B)-Bel(B)=0.48+2/20(1-0.48)=0.53.

5.12 ¿¼Éú¿¼ÊԳɼ¨µÄÂÛÓòΪ{A,B,C,D,E}£¬Ð¡Íõ³É¼¨ÎªA¡¢ÎªB¡¢ÎªA»òBµÄ»ù±¾¸ÅÂÊ·Ö±ð·ÖÅäΪ0.2¡¢0.1¡¢0.3¡£Bel({C,D,E})=0.2¡£Çë¸ø³öBel({A,B})¡¢Pl({A,B})ºÍf1({A,B})¡£

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M({A})=0.2, M({B})=0.1, M({A,B})=0.3 Ôò

Bel({A,B})=M({A,B})+M({A})+M({B})+M(?)=0.6 Pl({A,B})=1-Bel(?{A,B})=1-Bel({C,D,E})=0.8

|{A,B}|F({A,B})=Bel({A,B})+(Pl({A,B})-Bel({A,B})

|?| =0.6+2/5(0.8-0.6)=0.68.

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