CÓïÑÔ±à³ÌÌâÄ¿1

£¨1000£©.

Description

Calculate a+b

Input

Two integer a,b (0<=a,b<=10)

Output

Output a+b

Sample Input

1 2

Sample Output

3

£¨1001£©

Description

There is a famous railway station in PopPush City. Country there is

incredibly hilly. The station was built in last century. Unfortunately, funds were extremely limited that time. It was

possible to establish only a surface track. Moreover, it turned out that the station could be only a dead-end one (see picture) and due to lack of available space it could have only one track.

The local tradition is that every train arriving from the direction A continues in the direction B with coaches

reorganized in some way. Assume that the train arriving from the direction A has N <= 1000 coaches numbered in increasing order 1, 2, ..., N. The chief for train reorganizations must know whether it is possible to marshal coaches continuing in the direction B so that their order will be a1, a2, ..., aN. Help him and write a program that decides whether it is possible to get the required order of coaches. You can assume that single coaches can be disconnected from the train before they enter the station and that they can move themselves until they are on the track in the direction B. You can also suppose that at any time there can be located as many coaches as necessary in the station. But once a coach has entered the station it cannot return to the track in the direction A and also once it has left the station in the direction B it cannot return back to the station.

Input

The input consists of blocks of lines. Each block except the last describes one train and possibly more requirements for its reorganization. In the first line of the block there is the integer N described above. In each of the next lines of the block there is a permutation of 1, 2, ..., N. The last line of the block contains just 0.

The last block consists of just one line containing 0.

Output

The output contains the lines corresponding to the lines with

permutations in the input. A line of the output contains Yes if it is possible to marshal the coaches in the order

required on the corresponding line of the input. Otherwise it contains No. In addition, there is one empty line after the lines corresponding to one block of the input. There is no line in the output corresponding to the last ``null'' block of the input.

Sample Input

5

1 2 3 4 5 5 4 1 2 3 0 6

6 5 4 3 2 1 0 0

Sample Output

Yes

No Yes

£¨1002£©

Description

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ÀýÈ磺¸øÄãµÄÊýÊÇ£º1¡¢ 2¡¢ 3¡¢ 3¡¢ 4¡¢ 4¡¢ 5¡¢ 5¡¢ 5 ¡¢6, ÆäÖÐÖ»ÓÐ6×éÊý£º1, 2, 3-3, 4-4, 5-5-5 and 6.

×µÄÊÇ5ÄÇ×飬³¤¶ÈΪ3¡£ËùÒÔÊä³ö3¡£

Input

µÚÒ»ÐÐΪÕûÊýt((1 ¡Ü t ¡Ü 10))£¬±íʾÓÐn×é²âÊÔÊý¾Ý¡£

ÿ×é²âÊÔÊý¾Ý°üÀ¨Á½ÐУ¬µÚÒ»ÐÐλÊý×éµÄ³¤¶Èn (1 ¡Ü n ¡Ü 10000)¡£µÚ¶þÐÐΪn¸öÕûÊý£¬ËùÓÐÕûÊýMiµÄ·¶Î§¶¼ÊÇ(1 ¡Ü Mi ¡Ü 2^32)

Output

¶ÔӦÿ×éÊý¾Ý£¬Êä³ö¸öÊý×î¶àµÄÊýµÄ³¤¶È¡£

Sample Input

1 10

1 2 3 3 4 4 5 5 5 6

Sample Output

3

1003

ÎÒÃÇÖªµÀ£¬¸ßÖлῼÊǰ´µÈ¼¶À´µÄ¡£ 90~100ΪA; 80~89ΪB; 70~79ΪC; 60~69ΪD; 0~59ΪE¡£

±àдһ¸ö³ÌÐò£¬¶ÔÊäÈëµÄÒ»¸ö°Ù·ÖÖÆµÄ³É¼¨t£¬½«Æäת»»³É¶ÔÓ¦µÄµÈ¼¶¡£ Input

ÊäÈëÊý¾ÝÓжà×飬ÿ×éÕ¼Ò»ÐУ¬ÓÉÒ»¸öÕûÊý×é³É. Output

¶ÔÓÚÿ×éÊäÈëÊý¾Ý£¬Êä³öÒ»ÐС£Èç¹ûÊäÈëÊý¾Ý²»ÔÚ0~100·¶Î§ÄÚ£¬ÇëÊä³öÒ»ÐУº¡°Score is error!¡±¡£ Sample Input 56 67 100 123

Sample Output

E D A

Score is error! ´ð°¸

#include int main() { int score; while(scanf(\=EOF) {

if(score>=90&&score<=100) printf(\ else if(score>=80&&score<90) printf(\ else if(score>=70&&score<80) printf(\ else if(score>=60&&score<70) printf(\ else if(score>=0&&score<60) printf(\ else printf(\error!\\n\ } return 0; }

1005

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µÚÒ»ÐÐΪÁ½¸öÕûÊým, n(1¡Üm, n¡Ü1000)£¬·Ö±ð´ú±íÊý×éf[], g[]µÄ³¤¶È¡£ µÚ¶þÐÐÓÐm¸öÔªËØ£¬ÎªÊý×éf[]¡£ µÚÈýÐÐÓÐn¸öÔªËØ£¬ÎªÊý×ég[]¡£ Output

Êý×éµÄ×î¶Ì¾àÀë Sample Input 5 5

1 2 3 4 5 6 7 8 9 10 Sample Output

1

´ð°¸£º

#include #include int main() { int

m,n,f[1500],g[1500],min,i,j; scanf(\ for(i=0;i

if(min>abs(f[i]-g[j])) min=abs(f[i]-g[j]); printf(\ return 0; } 1035

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YUANzi1987£¬Õâ¸öÃÜÂëÊÇËûµÄÃû×ֺͳöÉúÄê·Ý£¬ÔõôÍü¶¼Íü²»ÁË£¬¶øÇÒ¿ÉÒÔÃ÷Ä¿Õŵ¨µØ·ÅÔÚÏÔÑ۵ĵط½¶ø²»±»±ðÈËÖªµÀÕæÕýµÄÃÜÂë¡£

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Output

Êä³öÔ¨×ÓÕæÕýµÄÃÜÎÄ¡£

Sample Input

YUANzi1987

Sample Output

zvbo941987 1036

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Input

²âÊÔÊý¾Ý°üÀ¨¶à¸öʵÀý¡£

ÿ×éÊý¾Ý°üÀ¨7¸öʵÊý£¬´ú±íÆÀίÃǶԸÃÑ¡ÊֵįÀ·Ö¡£½ô½Ó×ÅÊÇÑ¡ÊÖµÄÃû×Ö£¬Ãû×ֵij¤¶È²»³¬¹ý30¸ö×Ö·û¡£ ÊäÈëÖ±µ½Îļþ½áÊø¡£

Output

Ëã³öÿλѡÊÖÃû×ÖºÍ×îÖյ÷֣¬½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö¡£

Sample Input

10 10 10 10 10 10 9 xiaoyuanwang 0 0 0 0 0 0 0 beast

Sample Output

xiaoyuanwang 10.00 beast 0.00 1037

JesseÊǸöÊýѧÃÔ£¬Ëû×îϲ»¶Ñо¿¡°¸çµÂ°ÍºÕ²ÂÏ롱£¬Òò´ËËûµÄ¼ÆËã»úÃÜÂëÒ²¶¼²ÉÓÃËØÊý¡£

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µÄÃÜÂ루ËûµÄ»úÆ÷ÉÏ´æ·ÅÁ˵Ú4½ìË´Óí±­´óѧÉú³ÌÐòÉè¼Æ¾ºÈüµÄÌâÄ¿£¡£©£¬ÐèÒªÉú³ÉÒ»¸ö×ÖµäÀ´°ïÖúÎÒÃÇÆÆ½â¡£ ÇëÄãÀ´±àдһ¸ö³ÌÐò°ïÖúÎÒÃÇ£¨ÒòΪÖÚËùÖÜÖªµÄÔ­ÒòÎÒÃÇÆÈÇÐÐèÒª»ñµÃÕâЩÌâÄ¿£©¡£

Input

1 Line 1:ÃÜÂëµÄλÊýn (1 ¡Ü n ¡Ü 9)¡£

2 Line 2:1->n¸ö²»Öظ´µÄÕûÊýÐòÁÐ (1 ¡Ü x[i] ¡Ü 9). ÊäÈë0½áÊø¡£

Output

°´´ÓСµ½´ó˳ÐòÊä³öËùÓеĽá¹û¡£ Èç¹ûÒ»¸ö½á¹ûҲûÓУ¬Êä³ö¡°NONE¡±¡£ ÿ×éÊý¾ÝºóÃæ¸úËæÒ»¸ö¿ÕÐС£

Sample Input

3

1 2 4 0

Sample Output

241 421 1038

¾ÓÈ»Óмٱң¡£¡£¡

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ÁË¡£ÏÖÔÚÖªµÀ¼Ù±ÒµÄÖØÁ¿±ÈÕæ±ÒµÄÖÊÁ¿ÒªÇá¡£¸øÄãÒ»¸öÌìÆ½£¬ÇëÓÃ×î¿ìµÄʱ¼ä°ÑÄǸö¿É¶ñµÄ¼Ù±ÒÕÒ³öÀ´¡£ Input

1¡Ün¡Ü230,ÊäÈë0½áÊø³ÌÐò¡£ Output

×îÉÙÒª³Æ¼¸´ÎÒ»¶¨ÄܰÑÄǸö¼Ù±ÒÕÒ³öÀ´¡£

Sample Input 3 12 0

Sample Output 1 3 Hint

ʾÀý1Öй²ÓÐ3öӲ±Ò£¬ËùÒÔÈÎÒâÈ¡2¸ö·ÅÌìÆ½ÉϳÆÁ¿Ò»Ï¡£ ÒòΪ¼Ù±ÒµÄÖØÁ¿±È½ÏÇá¡£

1 Èç¹ûÌìÆ½²»Æ½ºâ£¬Ôò½ÏÇáµÄÄÇö¾ÍÊǼٱҡ£

2 Èç¹ûÌìÆ½Æ½ºâ£¬Ôò˵Ã÷ÕâÁ½Ã¶Ó²±Ò¶¼ÊÇÕæµÄ£¬¶øÊ£ÏÂÄÇöÊÇ¼Ù±Ò 1039

Description

¼Ä¾ÓзÓ뺣¿ûÊÇÒ»¶ÔºÏ×÷»¥ÖúµÄ¹²ÆÜ»ï°é¡£º£¿ûÊǼľÓз×î³ÆÖ°µÄÃÅÎÀ¡£ËüÓÃÓж¾µÄ´¥½ÇÈ¥òØÄÇЩ¸ÒÀ´¿¿½üËüÃǵÄËùÓж¯Î±£»¤¼Ä¾Óз¡£¶ø¼Ä¾Ó

зÔò±³×ÅÐж¯À§Äѵĺ£¿û£¬ËijöÃÙʳ£¬Óи£Í¬Ïí¡£

µ«²¢²»ÊÇËùÓмľÓзºÍº£¿û¶¼¿ÉÒÔ×ö´îµµµÄ¡£ÄǾÍÒª¿´º£¿ûµÄÉíÌåÊDz»ÊÇ·ûºÏ¼Ä¾ÓзµÄÂݿǡ£

º£¿ûµÄÉíÌåÊÇÓÐñÞÖåµÄ£¬¶ø¼Ä¾ÓзµÄÂÝ¿ÇͬÑù°¼Í¹²»Æ½£¬ÎÒÃÇ¿ÉÒÔÓÃÒ»¸ö´óд×Öĸ×é³ÉµÄ×Ö·û´®À´±íʾËüÃǵĸߵͳ̶ȣ¬ÆäÖÐA´ú±í0£¬B´ú±í1£¬ÒÀ´ÎÀàÍÆ¡£ÎÒÃdzÆÁ½ÕßÏà¼ÓµÈÓÚ25µÄ¾ÍËãÊÇÎǺϣ¬±ÈÈçAºÍZÏàÎǺϣ¬BÓëYÎǺϣ¬ÒÀ´ÎÀàÍÆ¡£

Ö»Òªº£¿ûÉíÌåµÄ²¿·ÖÐòÁÐÓë¼Ä¾ÓзÍâ¿ÇµÄÐòÁÐÏàÎǺϣ¬¾Í³ÆËûÃÇ¿ÉÒÔÒ»ÆðÉú»î¡£ ±ÈÈç:

1.º£¿ûµÄñÞÖåÊÇ\£¬¼Ä¾ÓзÊÇ\¡£ÕâÑù£¬ËüÃǾͿÉÒÔÍêÈ«ÎǺÏÁË¡£ 2.º£¿ûµÄñÞÖåÊÇ

\£¬¼Ä¾ÓзÊÇ\¡£ÕâÑù£¬¼Ä¾Óз¿ÉÒԺͺ£¿ûµÄ²¿·ÖÐòÁÐ\ÏàÎÇºÏ (×¢Òâ:²¿·ÖÐòÁв»¸Ä±ä×Ö·ûÔ­À´µÄÏȺó˳Ðò£¬±ÈÈç\¾Í²»ÊÇËüµÄ²¿·ÖÐòÁÐ)¡£ 3.º£¿ûµÄñÞÖåÊÇ\£¬¼Ä¾ÓзÊÇ\¡£ÕâÑù£¬ËäÈ»º£¿û¿ÉÒԺͼľÓÐ·Ç°ÃæÒ»¶ÎÍêÈ«ÎǺϣ¬µ«Ëü±È¼Ä¾ÓзҪС£¬²»ÄÜÍêÈ«±£»¤¼Ä¾ÓзµÄ°²È«£¬ËùÓÐËüÃÇÊDz»Êʺϵġ£

4.º£¿ûµÄñÞÖåÊÇ\£¬¼Ä¾ÓзÊÇ\¡£ÕâÑù£¬ËüÃǾͿÉÒÔÍêÈ«²»ÎǺÏÁË¡£

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Input

ÊäÈë°üÀ¨¶à×é²âÊÔÊý¾Ý¡£

ÿ×é²âÊÔÊý¾Ý°üÀ¨Á½¸ö×Ö·û´®H¡¢J£¬·Ö±ð´ú±íº£¿ûµÄÍâ¿ÇºÍ¼Ä¾ÓзµÄÍâ

¿Ç¡£¿ÉÒÔ±£Ö¤ËüÃǵij¤¶È¶¼Ð¡ÓÚ100000¡£

ÊäÈëÒÔ0 0½áÊø¡£

Output

Èç¹û¼Ä¾ÓзºÍº£¿ûµÄÍâ¿ÇÄÜÎǺϣ¬¾ÍÊä³ö\£¬·ñÔòÊä³ö\¡£

Sample Input

ABCDEFG ZYXWVUT

AHBICJDKELFMGN ZYXWVUT ABCD ZYXWVUT

HIJKLMNOPQ ZYXWVUT 0 0

Sample Output

Yes Yes No No 1040

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ÓÎÏ·¿ªÊ¼ºó£¬ÈÃÐÂÈËÃÇÈÎÒâµØÕ¾³ÉÒ»ÅÅ(¿ÉÄÜ»áÓÐÁ½¸öÈËÕ¾ÔÚÁËͬһ¸ö¸ñ×ÓÀï)¡£µÈËûÃǶ¼Õ¾ºÃÒÔºó£¬Ë¾ÒÇ¿ªÊ¼¼ÆËãËûÃÇÿ¸öÈË×Ô¼ºµÄµÃ·Ö£¬¼Ç·Ö¹æÔòÊÇ£ºÄз½µÄ·ÖÊýµÈÓÚ°Ñ´Ó×Ô¼ºËùÕ¾µÄλÖÿªÊ¼Ò»Ö±ÀÛ¼Óµ½¿ªÍ·£¬Å®·½µÄ·ÖÊýµÈÓÚ´Ó×Ô¼ºËùվλÖÿªÊ¼Ò»Ö±ÀÛ¼Ó

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ÅöÇÉ£¬redraimentµÄ½ã½ãºÍ½ã·òÒ²ÔÚÄÇÌì½á»é£¬ÎªÁ˰ï½ã½ã¶áµÃ½±Æ·£¬

redraimentÀ´ÇëÄã°ï棬¼ÆËãÒ»ÏÂËû½ã½ã»ñµÃ½±Æ·ÓжàÉÙÖÖÕ¾·¨¡£

Input

ÊäÈë°üÀ¨¶à×é²âÊÔÊý¾Ý¡£ ÿ×é²âÊÔÊý¾Ý°üÀ¨Á½ÐС£

µÚÒ»ÐÐΪһ¸öÊý¾Ýn£¬¼´ÐÂÈ˵ĶÔÊý¡£µÚ¶þÐÐÓÐ2n¸öÊý¾Ý£¬´ú±íµØÉϵÄÊý×Ö¡£ÊäÈëÒÔ0½áÊø£¬ÕâÒ»Ðв»×ö´¦Àí¡£

Output

ÿ×éÊä³öÕ¼Ò»ÐС£ Êä³ö¹²Óм¸ÖÖÕ¾·¨

Sample Input

3

3 6 2 4 5 2 0

Sample Output

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Description

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1 2 3 2 2 2 1100

Description

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2

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Description

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Sample Output 1 2 3 4 1103

Description

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Sample Input 3 3 -4 2 4 0 1 2 -3 0

Sample Output -4 3 2 -3 2 1 0 1106

Description

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Sample Output 7.50 15.00 7.50 15.00 1 1107

Description

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Description

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Sample Output

abcdefg(max)fedcba

x(max)x(max)x(max)x(max)x(max) 1109

Description

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I Want To Get An Accepted 1110

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u:1 1113

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Sample Output

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? int main() ? { ?

int

x1,y1,x2,y2,x3,y3,x4,y4,i,j,t; ? int a[6]; ?

while(scanf(\%d%d%d%d%d%d\&y2,&x3,&y3,&x4,&y4)!=EOF) ? { ? a[0]=pem(x1,y1,x2,y2); ? a[1]=pem(x2,y2,x3,y3); ? a[2]=pem(x3,y3,x4,y4); ?

a[3]=pem(x4,y4,x1,y1);

? a[4]=pem(x1,y1,x3,y3); ? a[5]=pem(x2,y2,x4,y4); ? for(i=1;i<6;i++) ?

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1191

Description

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Sample Output

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Description

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Description

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Description

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Sample Output 1 2 3 4 5 ´ð°¸£º

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{ printf(\ s=s/10; } printf(\ return 0; } 1431

Description

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Sample Output 2 3 5 1432

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Description

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Description

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Description

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Description

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