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0301 ÔÚË®ÈÜÒºÖй²éîËá¼î¶ÔKaÓëKbµÄ¹ØÏµÊÇ---------------------------------------------------( ) (A) Ka¡¤Kb=1 (B) Ka¡¤Kb=Kw (C) Ka/Kb=Kw (D) Kb/Ka=Kw 0302 HPO42-µÄ¹²éî¼îÊÇ---------------------------------------------------------------------------------( (A) H2PO4- (B) H3PO4 (C) PO43- (D) OH- 0303 OH-µÄ¹²éîËáÊÇ------------------------------------------------------------------------------------( (A) H+ (B) H2O (C) H3O+ (D) O2- 0304 ÔÚÏÂÁи÷×éËá¼î×é·ÖÖÐ,ÊôÓÚ¹²éîËá¼î¶ÔµÄÊÇ----------------------------------------------( (A) HCN-NaCN (B) H3PO4-Na2HPO4 (C) +NH3CH2COOH-NH2CH2COO- (D) H3O+-OH- 0305 ÏÂÁи÷×é×é·ÖÖв»ÊôÓÚ¹²éîËá¼î¶ÔµÄÊÇ-----------------------------------------------------( (A) H2CO3ºÍCO32- (B) NH3ºÍNH2- (C) HClºÍCl- (D) HSO4- ºÍSO42- 0306 ÒÔϱíÊöÖдíÎóµÄÊÇ-----------------------------------------------------------------------------( (A) H2O×÷ΪËáµÄ¹²éî¼îÊÇOH- (B) H2O×÷Ϊ¼îµÄ¹²éîËáÊÇH3O+ (C) ÒòΪHAcµÄËáÐÔÇ¿,¹ÊHAcµÄ¼îÐÔ±ØÈõ (D) HAcµÄ¼îÐÔÈõ,ÔòH2Ac+µÄËáÐÔÇ¿ 0307 Ũ¶ÈÏàͬµÄÏÂÁÐÎïÖÊË®ÈÜÒºµÄpH×î¸ßµÄÊÇ----------------------------------------------( (A) NaCl (B) NaHCO3 (C) NH4Cl (D) Na2CO3 ) ) ) ) ) ) 0308 ÏàͬŨ¶ÈµÄCO32-¡¢S2-¡¢C2O42-ÈýÖÖ¼îÐÔÎïÖÊË®ÈÜÒº, Æä¼îÐÔÇ¿Èõ(ÓÉ´óÖÁС)µÄ˳ÐòÊÇ-------------------------------------------------------------------------------------------------------------( ) (ÒÑÖª H2CO3 pKa1 = 6.38 pKa2 = 10.25 H2S pKa1 = 6.88 pKa2 = 14.15 H2C2O4 pKa1 = 1.22 pKa2 = 4.19 ) (A) CO32->S2->C2O42- (B) S2->C2O42->CO32- (C) S2->CO32->C2O42- (D) C2O42->S2->CO32- 0309 Ë®ÈÜÒº³ÊÖÐÐÔÊÇÖ¸--------------------------------------------------------------------------------( ) (A) pH = 7 (B) [H+] = [OH-] (C) pH+pOH = 14 (D) pOH = 7 0310 ÔÚÒ»¶¨µÄζÈÏÂ,»î¶ÈϵÊýÓëË®ºÏÀë×Ó°ë¾¶µÄ¹ØÏµÊÇË®ºÏÀë×Ó°ë¾¶Óú´ó,Àë×ӵĻî¶ÈϵÊý--------------------------------------------------------------------------------------------------------------( ) (A) Óú´ó (B) ÓúС (C) ÎÞÓ°Ïì (D) ÏÈÔö´óºó¼õС 0311 ÔÚH2C2O4ÈÜÒºÖÐ,ÏÂÁлî¶ÈϵÊýµÄÅÅÁÐ˳ÐòÕýÈ·µÄÊÇ------------------------------------( ) (A) ?(HC2O4-) > ?(H+) > ?(C2O42-) (B) ?(H+) > ?(HC2O4-) > ?(C2O42-) (C) ?(C2O42-) > ?(HC2O4-) > ?(H+) (D) ?(HC2O4-) > ?(C2O42-) > ?(H+) 0312 0.050mol/L AlCl3ÈÜÒºµÄÀë×ÓÇ¿¶ÈΪ----------------------------------------------------------( ) (A) 0.60 mol/L (B) 0.30 mol/L (C) 0.15 mol/L (D) 0.10 mol/L 0313 º¬0.10 mol/L HAc-0.10 mol/L NaAc-0.20 mol/L NaClÈÜÒºÖеÄÀë×ÓÇ¿¶ÈΪ----------( ) (A) 0.60 mol/L (B) 0.40 mol/L (C) 0.30 mol/L (D) 0.20 mol/L 0314 ijMA2ÐÍ(M2+¡¢A-)µç½âÖÊÈÜÒº,ÆäŨ¶Èc(MA2) = 0.10mol/L, Ôò¸ÃÈÜÒºµÄÀë×ÓÇ¿¶ÈΪ--------------------------------------------------------------------------------------------------------------( ) (A) 0.10 mol/L (B) 0.30 mol/L (C) 0.40 mol/L (D) 0.60 mol/L 0315 Ó°ÏìÆ½ºâ³£ÊýµÄÒòËØÊÇ--------------------------------------------------------------------------( ) (A) ·´Ó¦ÎïºÍ²úÎïµÄŨ¶È (B) ÈÜÒºµÄËá¶È (C) ÎÂ¶È (D) ´ß»¯¼Á 0316 ÔÚÒ»¶¨Î¶ÈÏÂ,Àë×ÓÇ¿¶ÈÔö´ó,ÈõËáµÄ±ê׼ƽºâ³£ÊýKa½«---- (A) Ôö´ó (B) ¼õС (C) ÎÞÓ°Ïì (D) ¼õСÖÁÒ»¶¨³Ì¶ÈºóÇ÷ÓÚÎȶ¨ 0317 ÔÚÒ»¶¨Î¶ÈÏÂ,Àë×ÓÇ¿¶ÈÔö´ó,´×ËáµÄŨ¶È³£ÊýKa½«------------------------------------( ) (A) Ôö´ó (B) ¼õС (C) ²»±ä (D) ¼õСÖÁÒ»¶¨³Ì¶ÈºóÇ÷ÓÚÎȶ¨ 0318 C¦È( ) Ò»ÔªÈõËáµÄ½âÀë³£ÊýµÄÁ½ÖÖÐÎʽ©¤©¤±ê׼ƽºâ³£ÊýKaÓë»ìºÏ³£ÊýKa,ËüÃǵĹØÏµÊÇ-------------------------------------------------------------------------------------------------------------( ) (A) (C) 0319 ÒÑÖªH3AsO4µÄpKa1= 2.2, pKa2= 6.9, pKa3= 11.5,ÔòÔÚ pH=7.0ʱ, ÈÜÒºÖÐ[H3AsO4]/[AsO43-]µÈÓÚ--------------------------------------------------------------------------------------------------------( ) (A) 100.4 (B) 10-0.4 (C) 10-5.2 (D) 10-4.8 ¦ÈM¦ÈMKa > Ka (B) Ka< Ka ¦ÈMKa = Ka (D) AÓëB¾ùÓпÉÄÜ ¦ÈM0320 Èô¶¯ÂöѪµÄpH=7.40, [HCO3-] = 0.024 mol/L, ÒÑÖªH2CO3µÄpKa1 = 6.38, pKa2 = 10.25, Ôò[H2CO3]Ϊ-----------------------------------------------------------------------------------------------( ) (A) 2.3¡Á10-2mol/L (B) 2.3¡Á10-3mol/L (C) 4.6¡Á10-2mol/L (D) 4.6¡Á10-3mol/L 0321 ÔÚÁ×ËáÑÎÈÜÒºÖÐ,HPO42-Ũ¶È×î´óʱµÄpHÊÇ-----------------------------------------------( ) (ÒÑÖªH3PO4µÄ½âÀë³£ÊýpKa1 = 2.12, pKa2 = 7.20, pKa3 = 12.36) (A) 4.66 (B) 7.20 (C) 9.78 (D) 12.36 0322 ÒÑÖªH3PO4µÄpKa1 = 2.12, pKa2 = 7.20, pKa3 = 12.36¡£½ñÓÐÒ»Á×ËáÑÎÈÜÒºµÄpH = 4.66, ÔòÆäÖ÷Òª´æÔÚÐÎʽÊÇ-------------------------------------------------------------------------------------( ) (A) HPO42- (B) H2PO4- (C) HPO42- + H2PO4 (D) H2PO4-+ H3PO4 0323 ÒÑÖªH3PO4µÄpKa1 = 2.12, pKa2 = 7.20, pKa3 = 12.36¡£½ñÓÐÒ»Á×ËáÑÎÈÜÒº, ²âµÃÆäpH = 7.0,ÔòÆäÖ÷Òª´æÔÚÐÎʽÊÇ----------------------------------------------------------------------------------( ) (A) H3PO4+H2PO4- (B) H2PO4-+HPO42- (C) H3PO4+HPO42- (D) HPO42-+PO43- 0324 ij²¡ÈËÍÌ·þ10g NH4Cl 1Сʱºó, ËûѪҺµÄpH = 7.38¡£ÒÑÖªH2CO3µÄ pKa1 = 6.38, pKa2 = 10.25¡£´ËʱËûѪҺÖÐ[HCO3-]/[H2CO3]Ö®±ÈΪ-------------------------------------------------( ) (A) 1/10 (B) 10 (C) 1/2 (D) 2 0325 ¶þÒÒÈý°±ÎåÒÒËá( ETPA, ÓÃHL±íʾ)µÄpKa1~pKa5·Ö±ðÊÇ1.94¡¢2.87¡¢4.37¡¢8.69ºÍ10.56, ÈÜÒºÖеÄH3L2-×é·ÖŨ¶È×î´óʱµÄpHÊÇ---------------------------------------------------------( ) (A) 2.87 (B) 3.62 (C) 5.00 (D) 9.62 0326 µ±pH = 5.00ʱ,0.20 mol/L¶þÔªÈõËá(H2A)ÈÜÒºÖÐ, H2AµÄŨ¶ÈΪ---------------------( ) (ÉèH2AµÄpKa1 = 5.00, pKa2 = 8.00) (A) 0.15 mol/L (B) 0.10 mol/L (C) 0.075 mol/L (D) 0.050 mol/L 0327 Óмס¢ÒÒ¡¢±ûÈýƿͬÌå»ýͬŨ¶ÈµÄH2C2O4¡¢NaHC2O4ºÍNa2C2O4ÈÜÒº, ÈôÓÃHCl»òNaOHµ÷½ÚÖÁͬÑùpH,×îºó²¹¼ÓË®ÖÁͬÑùÌå»ý,´ËʱÈýÆ¿ÖÐ[HC2O4-]µÄ¹ØÏµÊÇ--------------------( ) (A) ¼×Æ¿×îС (B) ÒÒÆ¿×î´ó (C) ±ûÆ¿×îС (D) ÈýÆ¿ÏàµÈ 0328 pH = 7.00µÄH3AsO4ÈÜÒºÓйØ×é·ÖƽºâŨ¶ÈµÄ¹ØÏµÓ¦¸ÃÊÇ----------------------------( ) (ÒÑÖª H3AsO4 pKa1 = 2.20, pKa2 = 7.00, pKa3 = 11.50) (A) [H3AsO4] = [H2AsO4-] (B) [H2AsO4-] = [HAsO42-] (C) [HAsO42-] >[H2AsO4-] (D) [H3AsO4] >[HAsO42-]

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