¾«Æ·Îĵµ
1000liquid 800liquid + A2B(s)t / ¡æ600Liquid + A2B(s) + AB2(s)400A2B(s) +AB2(s)2000WB=50ʱµÄÀäÈ´ÇúÏßʱ¼ät / s 6. (1) ÔÚºãÈÝÏ£¬Ïõõ£°·µÄ·Ö½âÁ¿£¨Å¨¶È£©ÓëN2OÆøÌåµÄ·Öѹ³ÉÕý±È¡£ÒòΪ¿ªÊ¼Ê±Ã»ÓÐN2O£¬p0=0£¬¸ù¾ÝʵÑé½á¹û lg[p¡Þ/(p¡Þ £ p)] = k' t£¬¼´ÓÐlg[(p¡Þ£ p0)/(p¡Þ £ pt)] = k' t£¬´ËʽΪһ¼¶·´Ó¦Ê½lg(pA£¬0/pA)= k' t£¬¹Ê·´Ó¦¶ÔÏõõ£°·Îª1¼¶·´Ó¦£» (2) ¸ù¾ÝʵÑé½á¹û£ºlgt1/2?lg(0.6930.693)?pH?lg()?lgaH kk£¬¼´ ?t1/2+0.693aH0.693k'?k??aHkk'£¬£¬ ??¿ÉÖª·´Ó¦¶Ôa(H)Ϊ¸º1¼¶·´Ó¦£¬ËùÒÔ·´Ó¦ËÙÂʵÄ΢·Ö·½³ÌӦΪ ??k'cNONH?kcNONHc-1H2222? ËÄ¡¢ÎÊ´ðÌ⣺(¹²3СÌ⣬ ¹²10·Ö) 1. ´ð£º dS = ?Q/dT £º¿ÉÄæ¹ý³Ì ¦¤H = nCp,m(T2-T1) £ººãѹÇÒÈÈÈÝÓëζÈÎÞ¹Ø ¦¤G =¦¤H ¨C T¦¤S £ººãΠ2. ´ð£º±¬Õ¨ÓëÈȱ¬Õ¨ºÍÖ§Á´·´Ó¦Óйأ¬Ó°ÏìÒòËØÓëζȡ¢Ñ¹Á¦¡¢Å¨¶ÈÓйء£ 3. ´ð£ºÒÑ֪ˮÔÚ100 ¡æ ʱµÄ±¥ºÍÕôÆøÑ¹Îª101.325Pa, ¸ù¾Ý¿Ë-¿Ë·½³Ì ln(p¡¯/p)=-(?vapHm/R)(1/T¡¯-1/T) ¼´ ln(69kPa/101.325kPa)=-(41050J¡¤mol-1 /8.3145J¡¤K-1¡¤mol-1 )(1/T¡¯-1/373.15K) T¡¯= 362.62K ¾«Æ·Îĵµ
¾«Æ·Îĵµ
¾«Æ·Îĵµ